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3 years ago

15

What three things are the states of matter based upon?

2 answers:

stich3 [128]3 years ago

7 0

The three states of matter are solid, gas, and liquid.

PilotLPTM [1.2K]3 years ago

3 0

The three states of matter are the distinct physical forms that matter can take: solid, liquid, and gas.

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How fast is the sixth cosmic velocity?

denpristay [2]

<span>25,000 miles per hour

hope that this helps</span>

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3 years ago

At which position is the LOWEST potential energy?

Ad libitum [116K]

The answer is position 3, because it is at its lowest point.

Potential Energy is “stored energy.” It is energy that is ready to be converted or released as another type of energy. We most often think of potential energy as gravitational potential energy. When objects are higher up, they are ready to fall back down. When you stretch an object and it has a tendency to return to its original shape, it is said to have elastic potential energy. Chemical potential energy is the stored energy in a substance’s chemical structure that can be released in a chemical reaction or as heat.

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3 years ago

PLEASE HELP I HAVE NO TIME PLEASEEE DONT SKIP

Triss [41]

2m/s

it has to be 20 charecters just ignore this your answer is up there

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2 years ago

what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a p

Oksanka [162]

Answer:

6.53 m/s²

Explanation:

Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.

Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:

T = m₁a (1)

m₂g - T = m₂a (2)

substituting T = m₁a in equation 2:

m₂g - m₁a = m₂a

m₂a + m₁a = m₂g

a(m₁ + m₂) = m₂g

a = m₂g / (m₁ + m₂)

a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²

Both objects have an acceleration of 6.53 m/s²

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3 years ago

A contestants spin a wheel when it is their turn in a game show. One contestant gives the wheel an initial angular speed of 3.40

guajiro [1.7K]

Answer:

4.62 s

Explanation:

We are given that

Initial angular speed, $\omega=3.4 rad/s$

$\theta=1\frac{1}{4} rev=\frac{5}{4}\times 2\pi=2.5\pi rad$

$\omega'=0$

$\omega'^2-\omega^2=2\alpha \theta$

Substitute the values

$0-(3.4)^2=2\times 2.5\pi \alpha$

$\alpha=\frac{-(3.4)^2}{2\times 2.5\pi}=-0.736 rad/s^2$

$\omega'=\omega+\alpha t$

$0=3.4-0.736 t$

$-0.736t=-3.4$

$t=\frac{-3.4}{-0.736}=4.62 s$

Hence, the wheel takes 4.62 s to come to rest.

3 0

3 years ago