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MA_775_DIABLO [31]
3 years ago
8

PLEASE HELPPP!!!!! I need help immediately, some answer this question​

Physics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

A)It would stay stationery as the resultant force is 0.

B)It would move towards the right as the resultant force is 300N due right.

C)It would move left as the resultant force is 300N due left.

Explanation:

Please make it brainiest answer

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Please help me on my physics hw ​
MatroZZZ [7]

Answer:

1. 11 A

2. 240 V

3. 8 Ω

4. 60 C

5. 14400 C

Explanation:

1. Determination of the current.

Voltage (V) = 110 V

Resistance (R) = 10 Ω

Current (I) =?

V = IR

110 = I × 10

Divide both side by 10

I = 110 / 10

I = 11 A

2. Determination of the voltage

Current (I) = 3 A

Resistance (R) = 80 Ω

Voltage (V) =?

V = IR

V = 3 × 80

V = 240 V

3. Determination of the resistance.

Current (I) = 0.5 A

Voltage (V) = 4 V

Resistance (R) =?

V = IR

4 = 0.5 × R

Divide both side by 0.5

R = 4 / 0.5

R = 8 Ω

4. Determination of the charge

Current (I) = 2 A

Time (t) = 30 s

Charge (Q) =?

Q = it

Q = 2 × 30

Q = 60 C

5. Determination of the charge.

We'll begin by converting 20 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

20 mins = 20 × 60

20 mins = 1200 s

Finally, we shall determine the charge as follow:

Current (I) = 12 A

Time (t) = 1200 s

Charge (Q) =?

Q = it

Q = 12 × 1200

Q = 14400 C

6 0
3 years ago
In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2
evablogger [386]

Answer: hello your question is incomplete attached below is the complete question

answer :  1/2 KD^2  ( option A )

Explanation:

P.E ( potential energy ) = mgd

In case 1 P.E = 0   i.e. mgd = 0  

Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring

<u>The potential energy of the M in case 2 </u>

= P.E of M at rest + P.E of the spring

= 0 + 1/2 KD^2

4 0
3 years ago
g A small object of mass 2.5 g and charge 18 uC is suspended motionless above the ground when immersed in a uniform electric fie
kvasek [131]

Answer: 1361.11\ N/C,\text{upward}

Explanation:

Given

Mass of particle is m=2.5\ gm

Charge of particle is q=18\ \mu C

Electrostatic force must balance the weight of the particle

\lim_{n \to \infty} a_n \Rightarrow mg=qE\\\\\Rightarrow E=\dfrac{2.5\times 9.8\times 10^{-3}}{18\times 10^{-6}}\\\\\Rightarrow E=1361.1\ N/C

Direction of the electric field is in upward direction such that it opposes the gravity force.

4 0
3 years ago
1. Since sleep is so important, we might wonder why people so often fail to get a sufficient amount
ziro4ka [17]

Answer: 9/10

Explanation:

because it's really important and makes you energetic

8 0
3 years ago
Prominences and sunspots are both:
Vadim26 [7]

Answer:

C. Influenced by the Sun's electromagnetic field

Explanation:

"Sunspots occur in pairs because each is one side of a loop of the Sun's magnetic field that reaches the Sun's surface. Solar prominences are the plasma loops that connect two sunspots."

8 0
3 years ago
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