Answer:
1 mol of any compound (including of course CO2 and O2) contains 6.022*10^23 molecules
Therefore 0.5 mol of CO2 and O2 contains 3.01*10^23 molecules of each.
Answer:
Answer is 14.65
Refer below.
Explanation:
Refer to the picture for brief explanation.
Answer:
4.92°
Explanation:
The banking angle θ = tan⁻¹(v²/rg) where v = designated speed of ramp = 30 mph = 30 × 1609 m/3600 s = 13.41 m/s, r = radius of curve = 700 ft = 700 × 0.3048 m = 213.36 m and g = acceleration due to gravity = 9.8 m/s²
Substituting the variables into the equation, we have
θ = tan⁻¹(v²/rg)
= tan⁻¹((13.41 m/s)²/[213.36 m × 9.8 m/s²])
= tan⁻¹((179.8281 m²/s)²/[2090.928 m²/s²])
= tan⁻¹(0.086)
= 4.92°
Answer:
u = 10.63 m/s
h = 1.10 m
Explanation:
For Take-off speed ..
by using the standard range equation we have
R = 9.1 m
θ = 26º,
Initial velocity = u
solving for u
u = 10.63 m/s
for Max height
using the standard h(max) equation ..
h = 1.10 m
To find the answer it's (theoretical value - experimental value) / theoretical value
(238857-226316)/238857 = 5.25%
The answer is A) 5.25%
