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MA_775_DIABLO [31]
2 years ago
8

PLEASE HELPPP!!!!! I need help immediately, some answer this question​

Physics
1 answer:
Alex17521 [72]2 years ago
5 0

Answer:

A)It would stay stationery as the resultant force is 0.

B)It would move towards the right as the resultant force is 300N due right.

C)It would move left as the resultant force is 300N due left.

Explanation:

Please make it brainiest answer

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Light from a helium-neon laser (? = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a sc
Sladkaya [172]

Answer:

0.3376 mm

Explanation:

The computation of the spacing in mm between the slits is shown below:

As we know that

d = \frac{m\lambda L}{\Delta y}

where,

\lambda = wavelength

L = distance from the scrren

\Delta y = spanning distance

As there are 11 bright fingers seen so m would be

= 11 - 1

= 10

Now placing these values to the above formula

So, the spacing is

= \frac{(10)(633 \times 10^{-9})(3.2m)}{60 \times 10^{-3}}

= 0.3376 mm

We simply applied the above formula.

6 0
3 years ago
Read 2 more answers
Describe five things that you do to make yourself feel warmer or cooler.
stira [4]
Buy a fan or heater, get a blanket, take a shower, go outside, go by the fireplace
7 0
3 years ago
A sports car is advertised to be able to stop in a distance of 50.0 m from a speed is 99.0km/h. What is its acceleration in m/s2
Shtirlitz [24]
99.0km/h =27.5m/s (this is the initial speed)
The final speed is zero
The distance is 50.0m
Therefore you use the formula:
vfinal²=vinitial²+2ad
a=(vfinal²-vinitial²)/2d
 = (0²-27.5²)/(2x50.0)
 =-7.5625 or in correct sigdigs -7.56m/s²
Hope this helps!
4 0
3 years ago
A Michelson interferometer uses light from a sodium lamp. Sodium atoms emit light having wavelengths 589.0 nm and 589.6 nm. The
DIA [1.3K]

The distance mirror M2 must be moved so that one wavelength has produced one more new maxima than the other wavelength is;

<u><em>L = 57.88 mm</em></u>

<u><em /></u>

We are given;

Wavelength 1; λ₁ = 589 nm = 589 × 10⁻⁹ m

Wavelength 2; λ₂ = 589.6 nm = 589.6 × 10⁻⁹ m

We are told that L₁ = L₂. Thus, we will adopt L.

Formula for the number of bright fringe shift is;

m = 2L/λ

Thus;

For Wavelength 1;

m₁ = 2L/(589 × 10⁻⁹)

For wavelength 2;

m₂ = 2L/(589.6)

Now, we are told that one wavelength must have produced one more new maxima than the other wavelength. Thus;

m₁ - m₂ = 2

Plugging in the values of m₁ and m₂ gives;

(2L/589) - (2L/589.6) = 2

divide through by 2 to get;

L[(1/589) - (1/589.6)] = 1

L(1.728 × 10⁻⁶) = 1

L = 1/(1.728 × 10⁻⁶)

L = 578790.67 nm

L = 57.88 mm

Read more at; brainly.com/question/17161594

8 0
2 years ago
When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards
aksik [14]

Answer:

51.85m/s

Explanation:

Given parameters:

Mass of ball  = 0.0459kg

Force  = 2380N

Time taken  = 0.001s

Unknown:

Speed of the ball afterwards  = ?

Solution:

To solve this problem, we use Newton's second law of motion:

   F = m x \frac{v - u}{t}  

F is the force

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

        2380  = 0.0459 x \frac{v- 0}{0.001}  

        0.0459v  = 2.38

                   v = 51.85m/s

8 0
3 years ago
Read 2 more answers
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