Answer:
Noble gas Electronic configuration of arsenic:
As₃₃ = [Ar] 3d¹⁰ 4s² 4p³
Explanation:
Arsenic is metalloid.
Its atomic number is 33.
Its atomic mass is 75 amu.
Its symbol is As.
It is usually present in combine with sulfur and metals.
it is used in bronzing.
It is also used for hardening.
Electronic configuration:
As₃₃ = Is² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p³
Noble gas Electronic configuration:
As₃₃ = [Ar] 3d¹⁰ 4s² 4p³
Noble gas electronic configuration is shortest electronic configuration by using the noble gas elements full octet electronic configuration.
The equation that shows the formation of chromium (ii) ion from neutral chromium atom is as follow
Cr ---> cr^2+ + 2e-
Cr^2+ is the chromium ion with oxidation state of two which is one of the common ion of chromium. Other common ion of chromium include chromium of oxidation state 6 and 3
The theoretical yield of I2 in the reaction would be 0.23 g
<h3>Theoretical yield</h3>
This refers to the stoichiometric yield of a reaction.
From the equation of the reaction:
Ca(IO3)2 + 10 KI + 12 HCl → 6 I2 + CaCl2 + 10 KCl + 6 H2O
The mole ratio of Ca(IO3)2 and I2 is 1: 6
Mole of 15.00 mL, 0.0100 M Ca(IO3)2 = 15/1000 x 0.0100
= 0.00015 mole
Equivalent mole of I2 = 0.00015 x 6
= 0.009 mole
mass of 0.0009 I2 = 0.0009 x 253.809
= 0.23 g
More on stoichiometric calculations can be found here: brainly.com/question/6907332
