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3 years ago

8

202H8(9) + 7 O2(g) > 4CO2(g) + 6 H2O(9).

1 answer:

lilavasa [31]3 years ago

4 0

since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.

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How do you convert moles of a compound to mass?

laiz [17]

Answer:

Divide the mass of the compound in grams by the molar mass you just calculated. The answer is the number of moles of that mass of compound

Explanation:

3 0

4 years ago

2 questions<br> Popeyes or KFC<br> Mcdonalds, Wendys, Burger King, Shake Shack, or Chick Fil A

Ymorist [56]

Answer:

Chick-fli-a

Explanation:

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3 years ago

Read 2 more answers

18. What is the percent by mass sugar of a solution made by dissolving 12.45 grams of sugar in 100 grams of water?

Fantom [35]

The percent by mass sugar of a solution : 11.07%

<h3>Further explanation</h3>

Given

mass of sugar = 12.45 g

mass of water = 100 g

Required

The percent by mass

Solution

Mass of solution :

$\tt mass~sugar+mass~water=12.45+100=112.45~g$

Percent mass of sugar :

$\tt \%mass=\dfrac{mass~sugar}{mass~solution}\times 100\%\\\\\%mass=\dfrac{12.45}{112.45}\times 100\%=11.07\%$

6 0

3 years ago

Suppose you had used carbon tetrachloride, a liquid of density 2.20 g/mL, to determine the actual volume measured by your pipet.

VARVARA [1.3K]

Answer:

Carbon tetrachloride would be 2.2 fold heavier than water

Explanation:

Carbon tetrachloride (2.20g/mL) is denser than water (1.00g/mL)

4 0

3 years ago

Which of the following ions is formed when a base is dissolved in a solution?

Aneli [31]

Answer:

$\huge\boxed{\sf OH-}$

Explanation:

<u>According to Arrhenius concept of acid and base:</u>

"When a base in a solution, produces/yields OH- (Hydroxide) ions."

So, when a base is dissolved in a solution, it produces OH- ions.

<u>For example:</u>

NaOH ⇄ Na⁺ + OH⁻ (So, it is a base)

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

3 0

3 years ago