Se requieren preparar 1500 ml de una solución al 55% en masa de hidróxido de calcio, sabiendo que la densidad de dicha solución
1 answer:
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Answer: Option (c) is the correct answer.
Explanation:
A chemical reaction is defined as the reaction where a chemical bond will break in order to form a new bond due to the formation of a new substance.
For example,
Here, NaCl is the new substance that is formed. A chemical reaction will always bring change in chemical composition of a substance.
The production of hydrogen gas from water, the tarnishing of a copper penny, charging a cellular phone and burning a plastic water bottle are all chemical reactions.
Whereas a reaction where no change in chemical composition of a substance takes place is known as a physical reaction.
For example, chopping a log into sawdust will change the shape but it will not bring any change in chemical composition of the substance.
Thus, we can conclude that in the following list, only chopping a log into sawdust is not an example of a chemical reaction.
Answer:
Explanation:
First consider the mol to mol ratio, the mol of a substance is simply the count of atoms in respect to avagadros number (approx. 6.02 × 10²³ molecules) in the period table. 1 mol of an element is simply it's mass count in the periodic table.
Answer:
14 grams of calcium oxide would be produced by thermal decomposition of 25 grams of calcium carbonate.
Explanation:
You know:
CaCO₃ → CaO + CO₂
In the first place, by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) the following quantities react and are produced:
- CaCO₃: 1 mole
- CaO: 1 mole
- CO₂: 1 mole
Being:
- Ca: 40 g/mole
- C: 12 g/mole
- O: 16 g/mole
the molar mass of the compounds participating in the reaction is:
- CaCO₃: 40 g/mole + 12 g/mole + 3*16 g/mole= 100 g/mole
- CaO: 40 g/mole + 16 g/mole= 56 g/mole
- CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
Then, by stoichiometry of the reaction, the following mass amounts of the compounds participating in the reaction react and are produced:
- CaCO₃: 1 mole* 100 g/mole= 100 g
- CaO: 1 mole* 56 g/mole= 56 g
- CO₂: 1 mole* 44 g/mole= 44 g
You can then apply the following rule of three: if by stoichiometry of the reaction 100 grams of calcium carbonate CaCO₃ produce 56 grams of calcium oxide CaO, 25 grams of CaCO₃ how much mass of CaO will it produce?
mass of calcium oxide= 14 grams
<em><u> 14 grams of calcium oxide would be produced by thermal decomposition of 25 grams of calcium carbonate.</u></em>