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Finger [1]
3 years ago
15

Solve the following problem for the roots by using the quadratic formula. 2(6 - x) = x(x + 5)

Mathematics
1 answer:
stiv31 [10]3 years ago
3 0
Solve for x:
2 (6 - x) = x (x + 5)
Expand out terms of the left hand side:
12 - 2 x = x (x + 5)
Expand out terms of the right hand side:
12 - 2 x = x^2 + 5 x
Subtract x^2 + 5 x from both sides:
-x^2 - 7 x + 12 = 0
Multiply both sides by -1:
x^2 + 7 x - 12 = 0
x = (-7 ± sqrt(7^2 - 4 (-12)))/2 = (-7 ± sqrt(49 + 48))/2 = (-7 ± sqrt(97))/2:
Answer:  x = (-7 + sqrt(97))/2 or x = (-7 - sqrt(97))/2
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Evaluate p -q for p = 34 and q = -35
Setler [38]
69 is the answer . (34)- (-35)

5 0
3 years ago
Find the domain and range of y=-5x-1
harina [27]

Answer:

  • \mathrm{Domain\:of\:}\:-5x-1\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

  • \mathrm{Range\:of\:}-5x-1:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Step-by-step explanation:

Finding the domain:

The domain of a function is the set of possible input values for which the function is real and defined.

Given the function

y=-5x-1

The function has no undefined points nor domain constraints. Hence, the domain is

-\infty \:

i.e.

\mathrm{Domain\:of\:}\:-5x-1\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Finding the range:

The range of a function is the set of possible output values (dependent variable y values) for which a function is defined.

The range of polynomials with odd degree is all the real numbers.

Hence, the domain is

-\infty \:

i.e.

\mathrm{Range\:of\:}-5x-1:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

5 0
3 years ago
Please help I'm horrible at fractions and I need to finish this...<br> Solve and simplify
Tpy6a [65]

Answer:

your answer would be 1/24

Step-by-step explanation:

this is because if you half it you get 5/120

then divide each by 5 to get 1/24

hope it helps!!

7 0
3 years ago
Read 2 more answers
Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am
Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\frac{3}{4}x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.

Answer: L = 1; W = 9/4; A = 2.25;

Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:

A = x.y

A = x(-\frac{3}{4}.x + 3)

A = -\frac{3}{4}.x^{2}  + 3x

To maximize, we have to differentiate the equation:

\frac{dA}{dx} = \frac{d}{dx}(-\frac{3}{4}.x^{2}  + 3x)

\frac{dA}{dx} = -3x + 3

The critical point is:

\frac{dA}{dx} = 0

-3x + 3 = 0

x = 1

Substituing:

y = -\frac{3}{4}x + 3

y = -\frac{3}{4}.1 + 3

y = 9/4

So, the measurements are x = L = 1 and y = W = 9/4

The maximum area is:

A = 1 . 9/4

A = 9/4

A = 2.25

6 0
3 years ago
Algebraic 3 more than 5 times a number
artcher [175]

Answer:

5x+3

Step-by-step explanation:

substitute x for the unknown number

8 0
3 years ago
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