Answer:
a) From 10 to 11, Sarah rode 12 km in one hour. That means her velocity was 12 km/hr.
b) Sarah passed by her home at 12:45.
c) From 12 to 13, Sarah rode 15 km. Thus, her velocity was 15 km/hr. From 13 to 14 she rode 3 km. Thus, her velocity was 3 km/hr.
d) Her average velocity was 12+0+15+3/4, or 30/4 which is 7.5 km/hr.
C = 5/9(F - 32)
C = -30
-30 = 5/9(F - 32)
-30 = 5/9F - 160/9
-30 + 160/9 = 5/9F
-270/9 + 160/9 = 5/9F
-110/9 = 5/9F
-110/9 * 9/5 = F
- 990/45 = F
- 22 = F
C = 5/9(F - 32)
C = 130
130 = 5/9F - 160/9
130 + 160/9 = 5/9F
1170/9 + 160/9 = 5/9F
1330/9 = 5/9F
1330/9 * 9/5 = F
11970/45 = F
266 = F
So in Fahrenheit temp, the the car is protected between -22 F and 266 F
Multiply 2nd equation by 3 and add to first
9x-3y=-2
<u>-9x+3y=-9 +</u>
0x+0y=-7
0=-7
false
no solution
these lines aer paraalell so no solution
Answer:
C
Step-by-step explanation:
I think the answer would be 78 ... I could be wrong tho
