Answer:
Mass of water required to dissolve all KCl is 20.90 grams.
Explanation:
Mass of the sample = 41 g
Percentage of KCl impurity = 13%
Mass of KCl =![\frac{13g}{100}\times 41 g=5.33 g](https://tex.z-dn.net/?f=%5Cfrac%7B13g%7D%7B100%7D%5Ctimes%2041%20g%3D5.33%20g)
Solubility of
= 7.1 grams per 100 grams of water at 20°C
Mass of ![KClO_3=41 g-5.33 g=35.67 g](https://tex.z-dn.net/?f=KClO_3%3D41%20g-5.33%20g%3D35.67%20g)
Solubility of
= 25.5 grams per 100 grams of water at 20°C
Mass of ![KCl=5.33 g](https://tex.z-dn.net/?f=KCl%3D5.33%20g)
Then 1 gram of
will dissolve in =
grams of water
Mass of water required to dissolve 5.33 grams of
:
![\frac{100}{25.5g}\times 5.33=20.90 g](https://tex.z-dn.net/?f=%5Cfrac%7B100%7D%7B25.5g%7D%5Ctimes%205.33%3D20.90%20g)
Answer:
C
Explanation:
Chemical formulas are used to describe the types of atoms and their numbers in an element or compound. The atoms of each element are represented by one or two different letters. When more than one atom of a specific element is found in a molecule, a subscript is used to indicate this in the chemical formula.
Cl2 is the answer because we are asked to find the chemical formulae of an element where as the rest H20,NaCl,NH3 are compounds(formed by the bonding of two or more chemical elements ). where as Cl2 is formed by the polar bonds between Cl and Cl atoms hence Cl2 is the chemical formulae of the element chlorine since it exists in that form not as Cl.
Answer:
During Glycolysis, there is one step where NADH + H+ is formed from NAD+ O F-6-P - F- 1,6-BP O PGAL – 1,3-BPGA O 2-PGA - PEP O 3-PGA → 2-PGA.
Answer:
26.81 moles
Explanation:
From the coefficients of the equation, we know that for every 2 moles of iron(III) oxide produced, 7 moles of oxygen are consumed.
So, the answer is 7.66(7/2), which is 26.81 mol.
Answer:
14,938 tablets.
Explanation:
WE divide:
1.21 kg / 81 mg
1.21 kg = 1,210 g = 1.210,000 mg.
So it is 1,210,000 / 81
= 14,938 tablets.