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3 years ago

Which of the following would form a nonelectrolyte solution in water? A. KCl B. NaNO3 C. C6H12O6 D. Cu2SO4

Chemistry

2 answers:

masha68 [24]3 years ago

6 0

Answer: Option (C) is the correct answer.

Explanation:

A compound formed by transfer of electrons between its atoms is known as an ionic compound.

Ionic compound when dissolve in water or polar solvent then they dissociate into ions and thus they are able to conduct electricity. Therefore, this type of solution is known as an electrolyte.

Whereas a covalent compound does not dissociate into ions. Hence, it is not able to conduct electricity. Thus, it does not act as an electrolyte.

Therefore, we can conclude that $C_{6}H_{12}O_{6}$ form a non-electrolyte solution in water.

ss7ja [257]3 years ago

3 0

<span>C. C6H12O6

</span>This compound is covalent, and all salts are ionic compounds.

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It has been suggested that hydrogen gas obtained by the decomposition of water might be a substitute for natural gas (principall

Aleks [24]

Answer:

Hydrogen: -141 kJ/g

Methane: -55kJ/g

The energy released per gram of hydrogen in its combustion is higher than the energy released per gram of methane in its combustion.

Explanation:

According to the law of conservation of the energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.

Qc + Qb = 0

Qc = -Qb [1]

We can calculate the heat absorbed by the bomb calorimeter using the following expression.

Q = C . ΔT

where,

C is the heat capacity

ΔT is the change in the temperature

<h3>Hydrogen</h3>

Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (14.3°C) = -162 kJ

The heat released per gram of hydrogen is:

$\frac{-162kJ}{1.15g} =-141 kJ/g$

<h3>Methane</h3>

Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (7.3°C) = -82 kJ

The heat released per gram of methane is:

$\frac{-82kJ}{1.50g} =-55kJ/g$

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3 years ago

Which is a diatomic molecule?<br><br> A)He<br><br> B)O2<br><br> C) NaCl<br><br> D)CuF2

katrin2010 [14]

Answer:

B. O2

Explanation:

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3 years ago

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Salt is an ionic compount. it

ElenaW [278]

Answer:

Explanation:

Ionic Compounds Are Balanced

Table salt is an example of an ionic compound. Sodium and chlorine ions come together to form sodium chloride, or NaCl. The sodium atom in this compound loses an electron to become Na+, while the chlorine atom gains an electron to become Cl-

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3 years ago

How much electric energy does a 40 W light bulb use if it is left on for 12 hours?

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480 hrs of electricity

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3 years ago

The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process. In the first step, manganese(I

ale4655 [162]

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:

$Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\$

Equation:

$3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\$

Calculating the amount of $MnCO_3$

$= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\= 13.1 \ kg$

For point b:

$Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\ of\ Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\$

$=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg$

Equation:

$3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\$

Calculating the amount of $MnO_2:$

$= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\= 6516 \ g \\\\=6.52 \ kg\\\\$

7 0

3 years ago