Answer:
1 - 5 is in the link, 6 is below
Explanation:
https://elemscience.jordandistrict.org/wp-content/uploads/sites/8/6.4.4.5.2-Return-of-the-Buttercup-Answers.pdf
6. The autumn buttercup only occurs in the Sevier River Valley in western Garfield County, Utah. The elevation range for the species is 6,374 - 7,000 feet.
Hey there!
To find the density of an object, you must use this formula:
Density=Mass/Volume
Knowing that your mass is 128.3741, the only information you need left would be to find the volume of the cube.
Because the side length of the cube is given, you can multiply the length three times in order to find its volume:
1.25*1.25*1.25
=1.953125
Now that you have your volume and mass, divide the mass by the volume to find the density:
128.3741/1.953125
=65.7275392
Therefore, your density would be 65.7275392 grams per inches cubed.
Critical thinking and skepticism are important to scientific inquiry because they help scientists to thoroughly examine all evidence before making their conclusions, this allows them to avoid errors. Critical thinking refers to the attitude of asking questions constantly, thoroughly examining information and evidence and making valid conclusions. While skepticism refers to an attitude of doubt. These attitudes are very important in scientific investigations; it helps scientists to be able to provide good evidence on which they base their conclusions.
:<span> </span><span>4 HCl + MnO2 → MnCl2 + 2 H2O + Cl2
(33.7 g MnO2) / (86.93691 g MnO2/mol) = 0.38764 mol MnO2
(45.3 g HCl) / (36.4611 g HCl/mol) = 1.2424 mol HCl
(a)
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant.
(b)
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2
(c)
(77.7% of 22.0 g Cl2) = 17.1 g Cl2</span>
Answer:
Cl₂ is the limiting reactant.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
N₂ + 3Cl₂ —> 2NCl₃
From the balanced equation above,
1 L of N₂ reacted with 3 L of Cl₂.
Finally, we shall determine the limiting reactant. This can be obtained as follow:
From the balanced equation above,
1 L of N₂ reacted with 3 L of Cl₂.
Therefore, 134 L of N₂ will react with = 134 × 3 = 402 L of Cl₂.
From the calculation made above, we can see that a higher volume (i.e 402 L) of Cl₂ than what was given (i.e 99 L) is needed to react completely with 134 L of N₂.
Therefore, Cl₂ is the limiting reactant and N₂ is the excess reactant.
