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3 years ago

What is the equilibrium constant for the following reaction? 3A + 2B <---> 2C

Chemistry

2 answers:

nordsb [41]3 years ago

5 0

<span>

K=C^2 / (A^3xB^2)
C simply means concentration of product C at equilibrium
same for reactants A and B</span>

kolbaska11 [484]3 years ago

5 0

Ke = [C]^2 /[A]^3 [B]^2 when the reaction has reached the equilibrium.

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The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

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$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

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$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

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$n_{(AcO)_2Cu} = 0.0053515 mol$

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$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

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