Explanation:
A catalyst lowers the activation energy of a reaction allowing them to proceed faster than they would naturally. Activation energy is the free energy that is required to be input in the reactant side to activate them to the transition state after which the reaction proceeds spontaneously to products.
An example of a catalyst is platinum, that is put in the exhaust of cars, to help convert carbon monoxide to carbon dioxide before it is emitted into the air.
Answer:
option C= patterns
Explanation:
The periodic table is helpful to identify the element readily. All the elements are arranged properly. The elements with same physical and chemical properties are placed in same group and period. Periodic table is also helpful to predict the properties of those elements which are not discovered yet. This table is also very helpful to balance the chemical equations. The horizontal rows are called periods while vertical column are called groups. There are seven periods and eighteen groups are in periodic table.
Trends in periodic table:
As we move left to right in a period the atomic radius is decreases with increase of atomic number. The ionization energy goes to increases from left to right in period because of greater hold of nuclear charge on valance electron, so that's way more energy is required to overcome this charge and to make the atom ionic.
From left to right in period electron affinity and electronegativity also increases.
As we move top to bottom in group ionization energy decreases with increase of atomic number because of large atomic radius. The valance electron require less energy to move free. The electron affinity and electronegativity also decreases from top to bottom.
Answer:
(a) 
(b) 
(c) 
Explanation:
Hello,
(a) In this case, since entropy remains unchanged, the constant
should be computed for air as an ideal gas by:


Next, we compute the final temperature:

Thus, the work is computed by:

(b) In this case, since
is given, we compute the final temperature as well:

And the isentropic work:

(c) Finally, for isothermal, final temperature is not required as it could be computed as:

Regards.
Answer:
Solid
Explanation:
As the temperature continues to drop, the matter forms a solid. Due to the solid's low kinetic energy, particles have no "time" to move around, the particles have more "time" to be attracted. Therefore, solids have the strongest intramolecular forces (because they have the strongest attraction).
Answer:
no, the correct answer is NaCI
Explanation:
you're welcome