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nlexa [21]
4 years ago
11

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing tin

and silver: sn(s)|sn2 (aq)||ag (aq)|ag(s)
Chemistry
1 answer:
mojhsa [17]4 years ago
8 0
  The  half  reactions    as  they  occur   at  each  electrode

is  as  follows

at  the  anode  Sn(s)  =sn^2+(aq)  +  2e  -
at  the  cathode  2  ag^+(aq)   + 2e -  =  2Ag (s)

net  cell  reaction  =   Sn (s)  +  2Ag^+(aq)  =  sn^2+ (aq) +  2  Ag  (s)
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A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,
alina1380 [7]

Answer:

it forms :

1. Gold ( Au )

2. Zinc nitrate ( Zn(NO3)2 )

Explanation:

When a chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms Gold and Zinc nitrate .

it's a single displacement reaction,

here's the balanced equation for above reaction :

3 Zn + 2 Au(NO3)3 =》3 Zn(NO3)2 + 2 Au

7 0
3 years ago
Read 2 more answers
Arrange the following units in decreasing order: nm,km,pm,Dm,mm,m,cm,hm,gm
goblinko [34]

The units are nm (nano-meter), km (kilo-meter), pm (pico-meter), dm (decimeter), mm (millimeter), m (meter), cm (centimeter), hm (hectometer) and gm (gigameter). Now we can express each of these units in terms of m.

1 nm = 10^{-9}m, 1 Km = 10^{3}m 1 pm = 10^{-12}m, 1 dm = 0.1 m, 1 mm = 0.001 m, 1 cm = 0.01 m, 1 hm = 100 m, 1 gm = 10^{9} m. Thus the decreasing unit will be

gm>km>hm>m>dm>cm>mm>nm>pm      

3 0
3 years ago
Determine if each salt will form a solution that is acidic, basic, or ph-neutral.
sveticcg [70]
Aluminium nitrate is acidic as its made by a weak base with a relatively stronger acid.

Hope that helps ;)
8 0
4 years ago
Pls help.
stepan [7]

Answer:

c or d

Explanation:

it says it was playing classic music

7 0
2 years ago
The monomer of poly(vinyl chloride) has the formula C2H3Cl. If there are 1,565 repeat units in a single chain of the polymer, wh
monitta

Answer:

\large \boxed{9.780 \times 10^{4}\text{ u}}

Explanation:

The molecular mass of a monomer unit is:

C₂H₃Cl = 2×12.01 + 3×1.008 + 35.45 = 24.02 + 3.024 + 35.45 = 62.494 u

For 1565 units,

\text{Molecular mass} = \text{1565 units} \times \dfrac{\text{62.494 u}}{\text{1 unit }} = \mathbf{9.780 \times 10^{4}}\textbf{ u}\\\\\text{The molecular mass of the chain is $\large \boxed{\mathbf{9.780 \times 10^{4}}\textbf{ u}}$}

8 0
3 years ago
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