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mrs_skeptik [129]
4 years ago
14

Solve for x. Use the completing the squares

Mathematics
1 answer:
Deffense [45]4 years ago
4 0
Hello there!
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x=-4± \sqrt{7}
x≈-1.35424868, -6.64575131

Hope this helps! :)
~Zain
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ch4aika [34]

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7 0
3 years ago
What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8
mariarad [96]
To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ 
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(3) \ ln \ a + ln \ b = ln \ (ab) \\
(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

The given equation is :
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ln \ x * ln \ e + ln \  x^{2} * ln \ e = 2 \ ln \ 8  ⇒⇒⇒⇒ rule (2)
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ln \ ( x*  x^{2} ) = ln \ 64          ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

x^{3} = 64 =  4^{3}
∴ x = 4


So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4


5 0
3 years ago
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pav-90 [236]
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