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romanna [79]
3 years ago
11

a diver descends from an elevation of 6 feet below sea level to an elevation of 98 feet below sea level in 4 equal intervals. Wh

at was the diver's change in elevation in each interval? Explain your answer.
Mathematics
1 answer:
dangina [55]3 years ago
8 0
98-6=92. This represents the amount of space he has to dive.
92/4=23. This represents your equal intervals. 


So the answer is that the diver dove in equal intervals of 23 ft.
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At 4:00 AM, the temperature is – 12 °F. If the temperature drops 3 °F per hour, what will the temperature be at 6:00 AM?
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3 0
3 years ago
Read 2 more answers
1.<br> When 3x2 - 2x + 7 is subtracted from 57-4x+10, AWO is the difference?
Eduardwww [97]

Combine like terms:

3 x 2 - 2x + 7 - 57 - 4x + 10

-34 - 6x

7 0
3 years ago
cam lobes are on sale at 4 different grocery stores. which store offers the lowest unit rate for cantaloupes in dollars per poun
timofeeve [1]

Answer:

Store 2

Step-by-step explanation:

Given

1.  $4.50 for 5 pounds

2. $1/5 for 1/3 pounds

3. $4.00 for 5 pounds

Required

Determine the store with the lowest unit rate

To do this, we simply divide the price by the weights in each store

For Store 1:

Unit\ Rate = \frac{\$4.50}{5\ lb}

Unit\ Rate = \$0.9/lb

For Store 2:

Unit\ Rate = \frac{\$1/5}{1/3\ lb}

Unit\ Rate = \$0.6/lb

For Store 3:

Unit\ Rate = \frac{\$4.00}{5\ lb}

Unit\ Rate = \$0.8/lb

<em>Comparing the unit rates of the three stores, we can conclude that store 2 offers the least unit rate</em>

8 0
3 years ago
Use the long division method to find the result when x^3+7x^2+12x+6x 3 +7x 2 +12x+6 is divided by x+1x+1. If there is a remainde
Aliun [14]

Answer:

By long division (x³ + 7·x² + 12·x + 6) ÷ (x + 1) gives the expression;

x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

Step-by-step explanation:

The polynomial that is to be divided by long division is x³ + 7·x² + 12·x + 6

The polynomial that divides the given polynomial is x + 1

Therefore, we have;

\ \ \ \ \ \  \ \ \ \ \ \ x^2 + 5\cdot x + 7\\ (x + 1) \sqrt{x^3 + 7\cdot x^2 +12\cdot x + 6} \\\ {} \  {} \ {}  \  \ {} \  {} \ {}  \ {} \  {} \ {}   \ {}     \ \ x^3 + 2 \cdot x^2 \\\  \ \ \ {} \   \ {} \  {} \ {}   \  \ {} \ {} \  \   \ {} \  {} \ {}  \  \ {} \  {} \ {}  \ \ 5 \cdot x^2 + 12\cdot x + 6\\  \ {} \  {} \ {}    \ {} \  {} \ {}  \ \ {} \ {} 5 \cdot x^2 + 5\cdot x\\\ 7\cdot x+6\\7\cdot x+7\\-1

(x³ + 7·x² + 12·x + 6) ÷ (x + 1) = x² + 5·x + 7 Remainder -1

Expressing the result in the form q(x) + \dfrac{r(x)}{b(x)}, we have;

(x^3 + 7\cdot x^2 + 12 \cdot x + 6)\div (x + 1) =  x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

4 0
3 years ago
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