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Anuta_ua [19.1K]
3 years ago
5

1. Choose two forces and compare and contrast these forces. You must provide two ways that they are alike and two ways that they

are different. You may make a list, write in paragraph form, or make a chart.
PLEASE ANSWER QUICK
Physics
2 answers:
Helen [10]3 years ago
7 0

Answer:

what are the forces ?  :l

Explanation:

Reptile [31]3 years ago
6 0

Answer: There are 4 forces. These are 1) Gravity, 2) Weak Nuclear Force, 3) Electromagnetism, and 4) Strong Nuclear Force.

Order of strength from weakest to strongest: Gravity, Weak Nuclear Force, Electromagnetism, Strong Nuclear Force

Explanation:

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A certain material has a high melting point and is malleable and shiny. It is most likely a _____.
Sonbull [250]
The answer is metal
4 0
4 years ago
Read 2 more answers
What is the maximum force that could be applied to anterior cruciate ligament (ACL) if it has a diameter of 4.8 mm and a tensile
vovangra [49]

Answer:

Maximum force, F = 1809.55 N

Explanation:

Given that,

Diameter of the anterior cruciate ligament, d = 4.8 mm

Radius, r = 2.4 mm

The tensile strength of the anterior cruciate ligament, P=100\times 10^6\ N/m^2=10^8\ Pa

We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

F=P\times A\\\\F=10^8\times \pi (2.4\times 10^{-3})^2\\\\F=1809.55\ N

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N

4 0
4 years ago
In Wagner’s opera Das Rheingold, the goddess Freia is ransomed for a pile of gold just tall enough and wide enough to hide her f
Vesna [10]

Answer:

Price=$7×10⁷

Explanation:

Step 1: Estimate the volume of the pile,

Step 2: Multiply it by the density to get its mass

Step 2: Then multiply the mass by the price per gram to get the total price

So

The average pile dimensions are=45.7×45×172.7

V=3.6*10^{5}cm^{3}\\  m_{g}=V_{p}=3.6*10^{5}*19.3=7*10^{6}g\\

Price=m×$10

Price=(7×10⁶)×$10

Price=$7×10⁷

5 0
3 years ago
. A car with a mass of 700-kg changes its speed from 10.0 m/s to 30.0 m/s in a displacement of 50.0 meters. Calculate the net fo
Nezavi [6.7K]

Answer:

5600N

Explanation:

Given parameters:

Mass of car  = 700kg

Initial velocity  = 10m/s

Final velocity  = 30m/s

Displacement  = 50m

Unknown:

Net force acting on the car  = ?

Solution:

To find the force acting on a body, it is pertinent we know the mass and acceleration.

 Force  = mass x acceleration

Now;

 Let us find the acceleration from the kinematics equations:

 v²  = u²  + 2aS

 v is the final velocity

 u is the initial velocity

 a is the acceleration

 S is the distance

  30²  = 10²  + (2 x a x 50)

 900 = 100 + 100a

      100a  = 800

           a  = 8m/s²

Therefore;

     Force  = 700 x 8  = 5600N

6 0
3 years ago
Scientific ideas about the solar system have changed over time. Which of them
Usimov [2.4K]

Answer:

Explanation:

If i'm not wrong and late it might be F

7 0
3 years ago
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