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Lostsunrise [7]
3 years ago
8

A 500-kg roller coaster car travels with some initial velocity along a track that is 5 m above the ground. The car goes down a s

mall hill and then coasts back up a higher hill. The second hill is 12 m above the ground. What must the initial velocity of the car be for the car to be going 3 m/s at the top of the second hill?
A.3.0 m/s
B.5.0 m/s
C.9.8 m/s
D.12 m/s
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

12m/s

Explanation:

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A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the acceleration the car presents during this time?
Art [367]

Answer:

1.02 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

a = (v – u) / t

a = (6.6 – 0) / 6.5

a = 6.6 / 6.5

a = 1.02 m/s²

Therefore, the acceleration of the car is 1.02 m/s²

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