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Lostsunrise [7]
3 years ago
8

A 500-kg roller coaster car travels with some initial velocity along a track that is 5 m above the ground. The car goes down a s

mall hill and then coasts back up a higher hill. The second hill is 12 m above the ground. What must the initial velocity of the car be for the car to be going 3 m/s at the top of the second hill?
A.3.0 m/s
B.5.0 m/s
C.9.8 m/s
D.12 m/s
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

12m/s

Explanation:

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What led scientists to the discovery of the strong nuclear force?
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Answer:

Explanation:

The concept of a new strong nuclear force was introduced. In 1935, the first theory for this new force was developed by the Japanese physicist Hideki Yukawa, who suggested that the nucleons would exchange particles between each other and this mechanism would create the force.

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What's a streak plate?
andrew-mc [135]
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3 0
3 years ago
A man walks 40 m North, then 70 m East and then 40
Anastasy [175]

Answer:

Displacement = 70 m towards east

Explanation:

Displacement is the shortest distance between the two points.

Let us say that he starts at the point O and travels in a path ABC.

If we join the initial and final point of the path travelled by him, it will give the displacement of the man.

Distance from O to A = 40 m

Distance from A to B = 70 m

Distance from B to C = 40 m

Distance from O to A = Distance from B to C

We want the displacement which is distance between the points O and C

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4 0
3 years ago
Read 2 more answers
Three people pull simultaneously on a stubborn donkey. jack pulls eastward with a force of 92.5 n, jill pulls with 89.9 n in the
alekssr [168]
Jack------------ force of 92.5 n   eastward-------Fjack(X)=92.5 n   Fjack(Y)=0

<span>jill ------------------------------- force of 89.9 n   northeast
Fjill(X)=cos45*89.9=63.57 n
</span>Fjill(Y)=sin45*89.9=63.57 n<span>

</span>jane -----------------------------force of 163 n   southeast
Fjane(X)=cos45*163=115.26 n
Fjane(X)=-sin45*163=-115.26 n

Ftotal (X)=92.5+63.57+115.26=271.33 n
Ftotal (Y)=0+63.57-115.26=-51.69 n

Fotal=((271.33)^2+(-115.26)^2) ^0.5=294.80 n southeast

the magnitude of the net force the people exert on the donkey. is 294.80 n southeast
7 0
3 years ago
A 0.111 kg hockey puck moving at 55 m/s is caught by a 80 kg goalie at rest. With what speed does the goalie slide on the (frict
Andrews [41]

Answer: 0.076 m/s

Explanation:

Momentum is conserved:

m v = (m + M) V

(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V

V = 0.076 m/s

After catching the puck, the goalie slides at 0.076 m/s.

6 0
3 years ago
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