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denis-greek [22]
2 years ago
6

If a star is moving away from you at a constant speed, how do the wavelengths of the absorption lines change as the star gets fa

rther and farther?
Physics
1 answer:
Minchanka [31]2 years ago
8 0

Answer:

they stay shifted the same amount to the red

Explanation:

Redshift is given by

z=\dfrac{\lambda_o-\lambda_e}{\lambda_e}

Where,

\lambda_o = Wavelength observed

\lambda_e = Wavelength emitted

Also

Transverse redshift is given by

1+z=\dfrac{1}{\sqrt{1-v^2/c^2}}

v = Velocity of object

c = Speed of light = 3\times 10^8\ m/s

So, if the velocity is constant the redshift remains the same

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Q 24, 25, 26 i dont get them and need answers for it
Alexandra [31]

Answer:

24) W = 75 [J]; 25) W = 1794[J]; 26) n = 8.8 (times) or 9 (times)

Explanation:

24) This problem can be solved by means of the following equation.

DU = Q-W\\

where:

DU = internal energy difference [J]

Q = Heat transfer [J]

W = work [J]  

Since there are no temperature changes the internal energy change is equal to zero

DU = 0

therefore:

Q = W\\

The work is equal to the heat transfered, W = 75 [J].

25) The heat transfer can be calculated by means of the following equation.

Q = m*c_{p}*DT\\where:\\m = mass = 0.4[kg]\\c_{p} = specific heat = 897[J/kg*K]\\DT= 5 [C]

Q = 0.4*897*5 = 1794[J]

Work is equal to heat transfer, W = 1794[J]

26) Each time the bag falls the potential energy is transformed into heat energy, which is released into the environment. In this way the potential energy is equal to the developed heat.

E_{p}=Q\\\\E_{p}=m*g*h

where:

m = mass = 0.5[kg]

g = gravity = 9.81[m/s^2]

h = 1.5 [m]

E_{p}=0.5*9.81*1.5\\E_{p}=7.36[J]

The heat developed can be calculated by means of the following equation.

Q=m*c_{p}*DT\\Q=0.5*130*1\\Q=65[J]

The number of times will be calculated as follows

n = 65/7.36

n = 8.8 (times) or 9 (times)

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Explanation:

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A 63 kg kg person starts traveling from rest down a waterslide 6.0 mm above the ground. At the bottom of the waterslide, it then
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