Answer:
a) 1.3 rad/s
b) 0.722 s
Explanation:
Given
Initial velocity, ω = 0 rad/s
Angular acceleration of the wheel, α = 1.8 rad/s²
using equations of angular motion, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
where
θ2 - θ1 = 53.2 rad
t2 - t1 = 7s
substituting these in the equation, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
53.2 =ω(0) * 7 + 1/2 * 1.8 * 7²
53.2 = 7.ω(0) + 1/2 * 1.8 * 49
53.2 = 7.ω(0) + 44.1
7.ω(0) = 53.2 - 44.1
ω(0) = 9.1 / 7
ω(0) = 1.3 rad/s
Using another of the equations of angular motion, we have
ω(0) = ω(i) + α*t1
1.3 = 0 + 1.8 * t1
1.3 = 1.8 * t1
t1 = 1.3/1.8
t1 = 0.722 s
Everything is in the universe.
That's what the word means.
Answer:
Hey
I have no idea when YOUR assignment is due.
Newtons 1rst law:
An object that has constant motion will remain at that speed unless acted on by an external force.
Newtons 2nd law:
F=ma (force=mass*acceleration)
Newtons 3rd law:
when a force is applied to an object, there will be an opposite but equal reaction.
Acceleration:
How much your speed increases/decreases per unit of time.
I wrote all that^
Answer:
(a): the mug hits the floor 0.752m away from the end of the bar.
(b): the speed of the mug at impact are:
V= 4.87 m/s
direction= 70.82º below the horizontal.
Explanation:
Vx= 1.6 m/s
Vy=?
h= 1.1 m
g= 9.8 m/s²
t is the fall time
![t=\sqrt{\frac{2*h}{g} }](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B2%2Ah%7D%7Bg%7D%20%7D)
t=0.47 sec
Vy= g*t
Vy= 4.6 m/s
![V=\sqrt{Vx^{2} +Vy^{2}](https://tex.z-dn.net/?f=V%3D%5Csqrt%7BVx%5E%7B2%7D%20%2BVy%5E%7B2%7D)
V= 4.87 m/s
α= tan⁻¹(Vy/Vx)
α= -70.82º