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2 years ago

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Choose the word from the drop-down menu that completes each sentence. A/An star system is made of two stars. A/An star system is

made of no more than a few thousand stars. A/An star system is made of more than a million stars. the answer in order is :
Binary
open cluster
globular cluster

2 answers:

Alenkinab [10]2 years ago

5 0

Answer:

Binary
Open cluster
Globular cluster

Explanation:

A star system is a group of stars that orbit one another, through he influence of gravitational force. The Earth's star system is called solar system.

kkurt [141]2 years ago

5 0

Answer:

globular cluster

mark brainliest pls!!!

Explanation:

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A 1280 kg car is moving 4.92 m/s. a 509 N force then pushes it forward for 28.7 m. what is its final KE?(unit=J)PLEASE HELP

laila [671]

Answer:

The answer to your question is: total energy = 30100.4 J

Explanation:

Kinetic energy (KE) is the energy due to the movement of and object, its units are joules (J)

Data

mass = 1280 kg

speed = 4.92 m/s

Force = 509 N

distance = 28.7 m

Formula

$KE = \frac{1}{2} mv^{2}$

Work = Fd

Process

- Calculate Kinetic energy

- Calculate work

- Add both results

KE = $\frac{1}{2} (1280)(4.92)^{2}$

KE = 15492.1 J

Work = (509)(28.7)

Work = 14608.3 J

Total = 15492.1 + 14608.3

Total energy = 30100.4 J

8 0

2 years ago

Read 2 more answers

Simon is riding a bike at 12 km/h away from his friend Keesha.He throws a ball at 5 km/h back to Keesha, who is standing still o

Tems11 [23]

I notice that even though we're working with frames of reference
here, you never said which frame the '5 km/hr' is measured in.

In fact ! You didn't even say which frame the '12 km/hr' of his
bike is measured in.

So there are several different ways this could go. I'll do it the way
I THINK you meant it, but that doesn't guarantee anything.

-- Simon is riding his bike at 12 km/hr relative to the sidewalk,
away from Keesha.

-- He throws a ball at Keesha, at 5 km/hr relative to his own face.

-- Keesha sees the ball approaching her at (12 - 5) = 7 km/hr
relative to the ground and to her.

5 0

3 years ago

One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe

Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

$\mu = \frac{m}{l}$

$\mu = \frac{8.79*10^{-3}}{70*10^{-2}}$

$\mu = 0.01255kg/m$

The expression for the wavelength of the standing wave for the second overtone is

$\lambda = \frac{2}{3} l$

Replacing we have

$\lambda = \frac{2}{3} (70*10^{-2})$

$\lambda = 0.466m$

The frequency of the sound wave is

$f_s = \frac{v}{\lambda_s}$

$f_s = \frac{344}{0.768}$

$f_s = 448Hz$

Now the velocity of the wave would be

$v = f_s \lambda$

$v = (448)(0.466)$

$v = 208.768m/s$

The expression that relates the velocity of the wave, tension on the string and linear mass density is

$v = \sqrt{\frac{T}{\mu}}$

$v^2 = \frac{T}{\mu}$

$T= \mu v^2$

$T = (0.01255kg/m)(208.768m/s)^2$

$T = 547N$

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the $n^{th}$ harmonic frequency is

$f_n = nf_1$

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

$n=3$

Then,

$f_3 = 3f_1$

Rearranging to find the fundamental frequency

$f_1 = \frac{f_3}{3}$

$f_1 = \frac{448Hz}{3}$

$f_1 = 149.9Hz$

7 0

2 years ago

One type of energy is the result of waves that travel through matter and cause particles in the matter to vibrate.Which type of

umka2103 [35]

sound energy hope this helps please give brainliest

3 0

3 years ago

If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it

hichkok12 [17]

<h3><u>Answer;</u></h3>

A. <em><u> $x = 2 +/- sqrt(17) / 2$ </u></em>

<h3><u>Explanation;</u></h3>

Using the equation given we can calculate the value of t, time taken by the basket ball to hit the ground.

$h = -16t^2 + 64t + 4 \\0 = -16t^2 + 64t + 4 \\16t^2 - 64t - 4 = 0 \\4(4t^2 - 16t - 1) = 0 \\4t^2 - 16t - 1 = 0 \\t = (-b +/- sqrt(b^2 - 4ac)) / 2a \\t = (16 +/- sqrt(256 + 16)) / 8 \\t = (16 +/- sqrt(272)) / 8 \\t = (16 +/- 4 sqrt(17)) / 8 \\t= 2 +/- sqrt(17) / 2$

8 0

3 years ago

Read 2 more answers