Answer:
19.95 J
Explanation:
The center of mass of the ladder is initially at a height of:

The center of mass of the ladder ends at a height of:
=L/2
So, the work done is equal to the change in potential energy which is:
W = PE = 
now 
therefore
W = [mgL/2]×[1 - sin(theta)]
W = [(7.30)(9.81)(2.50)/2]×[1-sin(51°)]
solving this we get
W = 19.95 J
Answer:
The bread will take 216.40 minutes to cool to 185°F
Explanation: Newton law of cooling
states that the rate of cooling of an object is inversely proportional to the difference of temperatures between the object and its surroundings i.e. dTdt=−kT, where t is the time taken and T is the difference of the temperatures between the object and its surroundings.
This gives us T as a function of t and is given by T(t)=ce−kt.
T(0)= Ce^-kt
C=35₩F- 185F= 165F
T(20) = 165×e^-20k=(350-70)
T(20)= e^-20k =280/165
-20k= ln(280/165)
-20k= ln(1.697)
-20k= 0.5289
K= 0.5289/20
K= 0.0264
If it cools at 185F in t minutes
165e^-0.0264×t=0.5
e^-0.0264t= 0.5/165
-0.0264t= on 3.03×10^-3
-0.0264t= -5.7129
t= 5.7129/0.0264
t=216.40minutes
Frequency and wavelength are two variables which are
indirectly proportional.
They are related in the following equation:
f = c / w
Where,
<span>f = frequency c =
speed of light w = wavelength</span>
Since c is constant, we can equate condition 1 and
condition 2:
f1 w1 = f2 w2
When w2 = 3 w1, then f2 becomes:
261.63 w1 = f2 (3 w1)
Cancelling w1:
f2 = 261.63 / 3
<span>f2 = 87.21 Hz</span>
(a) 89.8 m
First of all, let's convert the initial speed from km/h into m/s:

During the reaction time of
, the car still travels at constant speed, so it covers a distance of

Later, it slows down with acceleration

The distance covered in this second part can be found with the following equation:

where v=0 is the final speed of the car. Solving for S2,

So the total stopping distance is

(b) 79.2 m
This exercise is identical to the first part, except that this time the acceleration is

So, the distance covered while decelerating is

So the total stopping distance is

Answer:
the velocity of the ball at the peak is 0m/s
the acceleration of the ball at the peak is 0m/s²
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