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Vladimir [108]
3 years ago
12

The eyepiece of a compound telescope has a focal length of 12 cm and the objective lens has a focal length of 16 m. What is the

overall magnification of the telescope?
Physics
1 answer:
olasank [31]3 years ago
3 0

Answer:

The magnification is 133X

Explanation:

For a refractor telescope using convex lenses, the overall magnification os calculated as by dividing the focal length of the objective by that  of the eyepiece.

M = \frac{f(obj)}{f(eye)}

So:

M = \frac{16 m}{12 cm}

Care must be taken with the units, in this case they are in meters and centimeters, they should be converted into the same unit before calculating:

M = \frac{16 m}{0.12 m} = 133

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A uniform 2.50m ladder of mass 7.30kg is leaning against a vertical wall while making an angle of 51.0degree with the floor. A w
Zigmanuir [339]

Answer:

19.95 J

Explanation:

The center of mass of the ladder is initially at a height of:

h_1=\frac{L}{2}sin\theta

The center of mass of the ladder ends at a height of:

h_2= \frac{L}{2}sin90 =L/2

So, the work done is equal to the change in potential energy which is:

W = PE = mg(h_2-h_1)

now h_2-h_1= 1-sin\theta

therefore

W = [mgL/2]×[1 - sin(theta)]

W = [(7.30)(9.81)(2.50)/2]×[1-sin(51°)]

solving this we get

W = 19.95 J

8 0
3 years ago
A loaf of bread is removed from an oven at 350° F and cooled in a room whose temperature is 70° F. If the bread cools to 210° F
jasenka [17]

Answer:

The bread will take 216.40 minutes to cool to 185°F

Explanation: Newton law of cooling

states that the rate of cooling of an object is inversely proportional to the difference of temperatures between the object and its surroundings i.e. dTdt=−kT, where t is the time taken and T is the difference of the temperatures between the object and its surroundings.

This gives us T as a function of t and is given by T(t)=ce−kt.

T(0)= Ce^-kt

C=35₩F- 185F= 165F

T(20) = 165×e^-20k=(350-70)

T(20)= e^-20k =280/165

-20k= ln(280/165)

-20k= ln(1.697)

-20k= 0.5289

K= 0.5289/20

K= 0.0264

If it cools at 185F in t minutes

165e^-0.0264×t=0.5

e^-0.0264t= 0.5/165

-0.0264t= on 3.03×10^-3

-0.0264t= -5.7129

t= 5.7129/0.0264

t=216.40minutes

7 0
2 years ago
A certain string on a piano is tuned to produce middle c (f = 261.63 hz) by carefully adjusting the tension in the string. for a
Lemur [1.5K]

Frequency and wavelength are two variables which are indirectly proportional.

They are related in the following equation:

f = c / w

Where,

<span>f = frequency    c = speed of light          w = wavelength</span>

Since c is constant, we can equate condition 1 and condition 2:

f1 w1 = f2 w2

When w2 = 3 w1, then f2 becomes:

261.63 w1 = f2 (3 w1)

Cancelling w1:

f2 = 261.63 / 3

<span>f2 = 87.21 Hz</span>

7 0
3 years ago
Determine the stopping distances for an automobile with an initial speed of 95 km/h and human reaction time of 1.0 s : (a) for a
Rashid [163]

(a) 89.8 m

First of all, let's convert the initial speed from km/h into m/s:

u=95 km/h \cdot \frac{1000 m/km}{3600 s/h}=26.4 m/s

During the reaction time of t_1 = 1.0 s, the car still travels at constant speed, so it covers a distance of

S_1 = u t_1 = (26.4 m/s)(1.0 s)=26.4 m

Later, it slows down with acceleration

a=-5.5 m/s^2

The distance covered in this second part can be found with the following equation:

v^2 - u^2 = 2aS_2

where v=0 is the final speed of the car. Solving for S2,

S_2 = \frac{v^2-u^2}{2a}=\frac{0-(26.4 m/s)^2}{2(-5.5 m/s^2)}=63.4 m

So the total stopping distance is

S=S_1 + S_2 = 26.4 m+63.4 m=89.8 m

(b) 79.2 m

This exercise is identical to the first part, except that this time the acceleration is

a=-6.6 m/s^2

So, the distance covered while decelerating is

S_2 = \frac{v^2-u^2}{2a}=\frac{0-(26.4 m/s)^2}{2(-6.6 m/s^2)}=52.8 m

So the total stopping distance is

S=S_1 + S_2 = 26.4 m+52.8 m=79.2 m

7 0
3 years ago
A soccer player kicks a ball straight up at 40m/s
Oduvanchick [21]

Answer:

the velocity of the ball at the peak is 0m/s

the acceleration of the ball at the peak is 0m/s²

I would appreciate if my answer is chosen as a brainliest answer

7 0
2 years ago
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