In this closed system, a dog has sprinted to the top of a cliff. The dog (mass of 25kg) had been sprinting with a velocity of 13 m/s. Using what you know about potential and kinetic energy in systems, how tall is the cliff? Given:
mass =
height =
velocity =
Formula for a closed KE/PE system:
Plug in the numbers:
Answer (with Units):
1 answer:
According to this photo, or i can recommend this video that helped me by tapton physics.
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Answer:
1.#potential energy = PE, m = mass in kg, g = force of gravity, h= vertical height above the ground. ** means to the power of ie exponent. * means multiply.
PE = mgh
300 = m(10)(15)
m = 300/(10)(15)
m= 2kg
2. KE = 1/2 mv**2
= 1/2(50)(50)**2
= 2500 joules
Explanation
Is as in solution
Answer:
0.29D
Explanation:
Given that
F = G M m / r2
F = GM(6m) / (D-r)2
G Mm/r2 = GM(6m) / (D-r)2
1/r2 = 6 / (D-r)2
r = D / (Ö6 + 1)
r = 0.29 D
See diagram in attached file
Without a change in pressure V/T = V/T Before change = after change - expansion x = volume at m3 (0.5)/20 = x/45 .025 = x/45 .025 * 45 = x 1 = x The volume of this gas is 1 m3. Hope this helps :) also the gas expanded .5 of m3.
Gas or fog in the air due to evaporation. please vote my answer branliest. Thanks.
Answer:
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