The work that is required to increase the speed to 16 knots is 14,176.47 Joules
If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;
5.44×10^3 kg = 12 knots
For an increased speed to 16knots, we will have:
x = 16knots
Divide both expressions
To get the required work done, we will divide the mass by the speed of one knot to have:
Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules
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Answer:
Explanation:
For the cat to stay in place on the merry go round without sliding the magnitude of maximum static friction must be equal to magnitude of centripetal force
Where the r is the radius of merry-go-round and v is the tangential speed
but
So we have
Substitute the given values
So
Answer: The area of the parking lot is 14,400 meters squared.
Explanation:
We have the dimensions of the parking lot.
60m by 240m
The units used here are meters.
Now, if we want to know the area of the parking lot is equal to the product between the length and the width:
A = 60m*240m = 14,400 m^2
The area of the parking lot is 14,400 meters squared.
The answer is C as there is more force on the left side ( excess of 5 N) which therefore pushed it to the right with a force of 5 N!
