Answer:
Explanation:
Think about the equation for velocity. Its the change in position over the change in time. And now think about the formula for slope, its the change in y over the change in x. Now, if you have a position vs time graph, the slope is position over time, the direct formula for velocity. Therefore, the slope of a position vs time graph gives the velocity in that interval. You could take the derivative at that point and get the instantaneous velocity.
In the first argument, the only way to get a negative slope is if youre moving to the left of your initial position as you pass through time. So the claim isnt necessarily true. When you move away from the origin, that simply means youre moving through time.
In the second argument, a horizontal slope means the value is 0. That means there is a value of 0 for your velocity, aka standing still.
In the third argument, a positive slope means youre moving to the right of your initial position as you go through time.
The fourth one is incorrect. Speed is the magnitude of velocity, and the slope can be determined an any point besides vertical slopes, which would require time to literally stop.
I dont understand the very last part of what you posted, so try to make a decision based on what I just explained to you
Answer:
three times the original diameter
Explanation:
From the wire's resistance formula, we can calculate the relation between the diameter of the wire and its length:
![R=\rho\frac{l}{\pi \frac{d^2}{4}}\\d=\sqrt{\rho \frac{4 l}{\pi R}}\\](https://tex.z-dn.net/?f=R%3D%5Crho%5Cfrac%7Bl%7D%7B%5Cpi%20%5Cfrac%7Bd%5E2%7D%7B4%7D%7D%5C%5Cd%3D%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20l%7D%7B%5Cpi%20R%7D%7D%5C%5C)
Here, d is the wire's diameter,
is the electrical resistivity of the material and R is the resistance of the wire. We have ![l'=9l](https://tex.z-dn.net/?f=l%27%3D9l)
![d'=\sqrt{\rho \frac{4 l'}{\pi R}}\\d'=\sqrt{\rho \frac{4 (9l)}{\pi R}}\\d'=3\sqrt{\rho \frac{4 l}{\pi R}}\\d'=3d](https://tex.z-dn.net/?f=d%27%3D%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20l%27%7D%7B%5Cpi%20R%7D%7D%5C%5Cd%27%3D%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20%289l%29%7D%7B%5Cpi%20R%7D%7D%5C%5Cd%27%3D3%5Csqrt%7B%5Crho%20%5Cfrac%7B4%20l%7D%7B%5Cpi%20R%7D%7D%5C%5Cd%27%3D3d)
Well, first of all, wherever you got this question from has done
a really poor job of question-writing. There are a few assorted
blunders in the question, both major and minor ones:
-- 22,500 is the altitude of a geosynchronous orbit in miles, not km.
-- That figure of 22,500 miles is its altitude above the surface,
not its radius from the center of the Earth.
-- The orbital period of a synchronous satellite has to match
the period of the Earth's rotation, and that's NOT 24 hours.
It's about 3 minutes 56 seconds less ... about 86,164 seconds.
Here's my solution to the question, using some of the wreckage
as it's given, and correcting some of it. If you turn in these answers
as homework, they'll be marked wrong, and you'll need to explain
where they came from. If that happens, well, serves ya right for
turning in somebody else's answers for homework.
The satellite is traveling a circle. The circle's radius is 26,200 miles
(not kilometers) from the center of the Earth, so its circumference
is (2 pi) x (26,200 miles) = about 164,619 miles.
Average speed = (distance covered) / (time to cover the distance)
= (164,619 miles) / day
(264,929 km)
= 6,859 miles per hour
(11,039 km)
= 1.91 miles per second
(3.07 km)
Answer:
0.00188 m²
37500000
Explanation:
= Area of aorta
Radius of aorta = 0.01 m
= Velocity of blood through aorta = 0.3 m/s
= Area of capillaries
= Velocity of blood through capillaries = ![5\times 10^{-4}\ m/s](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E%7B-4%7D%5C%20m%2Fs)
= Radius of capillaries = ![4\times 10^{-6}\ m](https://tex.z-dn.net/?f=4%5Ctimes%2010%5E%7B-6%7D%5C%20m)
From continuity equation as the mass is conserved
![A_1v_1=A_2v_2\\\Rightarrow A_1=\frac{A_2v_2}{v_1}\\\Rightarrow A_1=\frac{\pi (10^{-3})^2\times 0.3}{5\times 10^{-4}}\\\Rightarrow A_1=0.00188\ m^2](https://tex.z-dn.net/?f=A_1v_1%3DA_2v_2%5C%5C%5CRightarrow%20A_1%3D%5Cfrac%7BA_2v_2%7D%7Bv_1%7D%5C%5C%5CRightarrow%20A_1%3D%5Cfrac%7B%5Cpi%20%2810%5E%7B-3%7D%29%5E2%5Ctimes%200.3%7D%7B5%5Ctimes%2010%5E%7B-4%7D%7D%5C%5C%5CRightarrow%20A_1%3D0.00188%5C%20m%5E2)
Effective cross sectional area of the capillaries is 0.00188 m²
Area of capillaries is also given by
![A_1=N\times \pi r_c^2\\\Rightarrow N=\frac{A_1}{\pi r_c^2}\\\Rightarrow N=\frac{\frac{\pi (10^{-3})^2\times 0.3}{5\times 10^{-4}}}{\pi\times (4\times 10^{-6})^2}\\\Rightarrow N=37500000](https://tex.z-dn.net/?f=A_1%3DN%5Ctimes%20%5Cpi%20r_c%5E2%5C%5C%5CRightarrow%20N%3D%5Cfrac%7BA_1%7D%7B%5Cpi%20r_c%5E2%7D%5C%5C%5CRightarrow%20N%3D%5Cfrac%7B%5Cfrac%7B%5Cpi%20%2810%5E%7B-3%7D%29%5E2%5Ctimes%200.3%7D%7B5%5Ctimes%2010%5E%7B-4%7D%7D%7D%7B%5Cpi%5Ctimes%20%284%5Ctimes%2010%5E%7B-6%7D%29%5E2%7D%5C%5C%5CRightarrow%20N%3D37500000)
The number of capillaries is 37500000
Examples<span> are hand lotion, mayonnaise, and milk. Foams have liquid and gas</span>