Question

Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. The length l of the bar obeys the following relation: l=1.0000+2.4×10−5T, where T is the number of degrees Celsius above room temperature. What is the change of the bar's length if the temperature is raised to 16.1 ∘C above room temperature?

Answer 1

Answer:

The change of the bar's length is $3.9\times10^{-4} m$

Explanation:

The bar length is a function of temperature T above room temperature:

$L(T)=1.0000+2.4\times10^{-5} T$

So, if we evaluate at T= 16.1 C above room temperature

$L(16.1)=1.0000+2.4\times10^{-5} (16.1)$

$L=1.00039 m$

Now we can find the change of the bar length with the difference of L and Lo (the length at room temperature)

$L- L_0=1.00039-1.0000 = 3.9\times10^{-4} m$