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Black_prince [1.1K]
4 years ago
10

(x^(2)-3x-54)/(x^(2)-18x+81)*(x^(2)+12x+36)/(x+16)

Mathematics
1 answer:
Kamila [148]4 years ago
4 0
<span>(x^(2)-3x-54)/(x^(2)-18x+81)*(x^(2)+12x+36)/(x+16)

</span>\frac{x^2-3x-54}{x^2-18x+81} * \frac{x^2+12x+36}{x+16} =\\  \\ = \frac{(x-9)(x+6)}{(x-9)^2} * \frac{(x+6)^2}{x+16} = \\  \\ = \frac{x+6}{x-9} * \frac{(x+6)^2}{x+16} = \\  \\ = \frac{(x+6)^3}{(x-9)(x+16)}<span>
</span>
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a) He will earn $584 for working 36 hours.

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B) 39 h

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He will earn $656 for working 39 hours.

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He will earn $728 for working 42 hours.

Keywords: addition, multiplication

Learn more about addition at:

  • brainly.com/question/7888686
  • brainly.com/question/8224301

#LearnwithBrainly

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