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Elanso [62]
3 years ago
8

What is the stationary point of y=9x+6x^2-4x^3.need help asap

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0
y=9x+6x^2-4x^3\\
y'=9+12x-12x^2\\
9+12x-12x^2=0\\
-12x^2+12x+9=0\\
4x^2-4x-3=0\\
4x^2-4x+1-4=0\\
(2x-1)^2=4\\
2x-1=2 \vee 2x-1=-2\\
2x=3 \vee 2x=-1\\
x=\frac{3}{2} \vee x=-\frac{1}{2}
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