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AnnZ [28]
4 years ago
13

What is a underlying problem affecting the fresh water supply?

Chemistry
2 answers:
sp2606 [1]4 years ago
7 0
 increased global populations would probably be a big one
Aneli [31]4 years ago
5 0

Answer:

There are several causes that lead to water scarcity:

1. Pollution

2.The drought.

3. Uncontrolled use of fresh water.

Explanation:

1. Pollution of both freshwater and land or air, since such contamination can seep into the water and affect the air.

2.Because of climate change, the appearance of droughts is strengthened, which is a prolonged period without rain, causing water shortages for both humans and crops or for industry.

3. Factories, for example, both small and large industries, on the other hand, wastefulness must also be counted in some houses, where water is sometimes wasted.

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A 10 mm Brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a) Compute the HB of this mat
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Explanation:

(a)  The given data is as follows.  

         Load applied (P) = 1000 kg

         Indentation produced (d) = 2.50 mm

         BHI diameter (D) = 10 mm

Expression for Brinell Hardness is as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

(b)     The given data is as follows.

               Brinell Hardness = 300

                Load (P) = 500 kg

               BHI diameter (D) = 10 mm

             Indentation produced (d) = ?

                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

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