Question

A technical machinist is asked to build a cubical steel tank that will hold 130l of water. calculate in meters the smallest possible inside length of the tank. round your answer to the nearest 0.001m .

Answer 1

The smallest possible inside length of the tank is about 0.507 m

Further explanation

Some units of length and its conversion that need to be recalled are:

$1 ~ foot = 30.48 ~ cm$

$1 ~ inch = 2.54 ~ cm$

$1 ~ foot = 12 ~ inches$

$1 ~ mile = 1609.34 ~ metres$

$1 ~ yard = 0,9144 ~ metres$

$1 ~\mu m = 1 \times 10^{-6} ~ m$

Let us now tackle the problem!

This problem is about conversion of units of volume.

$\boxed {1 ~ L = 1 ~ dm^3 = 1 \times 10^{-3} ~ m^3}$

$130 ~ L = 130 \times 10^{-3} ~ m^3 = 0,13 ~ m^3$

To find the length of the tank we can use the following formula.

$\text{Volume of Cube} = (\text{Side Length})^3$

$\text{Side Length} = \sqrt[3]{\text{Volume of Cube}}$

$\text{Side Length} = \sqrt[3]{0.13 ~ m^3}$

$\text{Side Length} \approx 0.507 ~ m$

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Answer details

Grade: High School

Subject: Physics

Chapter: Physical Quantities

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Length , Mass , Physical , Quantities , Conversion , Unit , cg , mg , kg

Answer 2

Answer:0.507m

To answer this question, you need to know how to calculate a cube volume. Cube volume is calculated by multiplying the length^3, make its unit become cubic meter.
In this case we know the volume is 130L and asked how long is the length in meter. Then you need to convert the liter into m3. The calculation would be:
V=R^3
130L= R^3
R= 3√(130m3/1000)
R= 5.065797/10 m
R= 0.506579m
Rounded up to 0.507m