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4 years ago

How do buffers work in the human body?

Chemistry

2 answers:

mariarad [96]4 years ago

6 0

Answer is: They can help prevent a deadly change in blood pH.

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

The normal pH in the mammals arterial blood is between 7.35 and 7.50, so acidosis occurs when arterial pH falls below 7.35. Acidosis is a process causing increased acidity (increased hydrogen ion or proton H⁺ concentration) in the blood and other body tissues.

Alkalosis occurs at a pH over 7.45.

zmey [24]4 years ago

5 0

Buffers in the human body can help to prevent a deadly change in blood pH.

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Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

Answer: The mass of lead iodide produced is 9.22 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

6 0

3 years ago

2Cu + O2 + 315kj - 2CuO. Is what kind of chemical reaction?

Naddika [18.5K]

There are three possibilities:

synthesis

redox (reduction/oxidation)

endothermic

3 0

4 years ago

How many liters of phosphine are produced when 34 L of hydrogen reacts with an excess of phosphorus under STP?

Keith_Richards [23]

Answer:

22.67 L of PH₃

Explanation:

The balanced equation is:

$P_4 (s) + 6H_2(g) \to 4PH_3(g)$

From the equation:

$34 L \times \dfrac{1 \ mol \ of H_2 }{22.4 \ L \ H_2} \times \dfrac{4 \ mol \ of \ PH_3}{6 \ mol \ H_2} \times \dfrac{22.4 \ L \ PH_3}{1 \ mol \ PH_3}$

= 22.67 L of PH₃

5 0

3 years ago

Which of the following is an example of radiation?

Lapatulllka [165]

I believe the best answer to that question wud be D. I cud b wrong

5 0

3 years ago

Convert 7.9 x 10^22 atoms of Ca to grams

Vika [28.1K]

Answer:

Mass = 5.24 g

Explanation:

Given data:

Number of atoms of Ca = 7.9×10²² atoms

Mass of Ca = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole contain 6.022×10²³ atoms

7.9×10²² atoms × 1 mol /6.022×10²³ atoms

1.31 ×10⁻¹ mol

0.131 mol

Mass of Ca:

Mass = number of moles × molar mass

Mass = 0.131 mol × 40 g/mol

Mass = 5.24 g

6 0

3 years ago