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3 years ago

. What factors should Margaret NOT consider when deciding how much powder to add to her glass of water?

Chemistry

1 answer:

makkiz [27]3 years ago

7 0

Answer is *color of the solute*

If your answers are: A Nature of the solvent

B Temperature

C Nature of the solute

D Color of the solute

And the explanation is: D Solubility can be affected by the nature of the solute and solvent, temperature, and pressure. The color of the solute is not a factor because it does not affect solubility

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For salt formation procedure crude lidocaine should be dissolved in diethyl ether and 2 ml of 2.2 M sulfuric acid should be adde

mixas84 [53]

Answer:

20 equivalents of sulfuric acid are needed to per equivalent of lidocaine.

Explanation:

To do this calculation we should take in account the key information given:

2 mL (0.02 L) of sulfuric acid (H2SO4) 2.2 M per 1 g of lidocaine (molecular weight=234.34 g/mol)

So we can calculate from here the number of moles of each compound needed for the procedure.

Starting with the sulfuric acid, we know that the molar concentration is defined as [concentration] =n(moles number)/V(volume).

So n=[concentration]*V, and therefore :

n(H2SO4)=2.2 M * 0.02 L=0.044 mol

While the moles of lidocaine can be calculated as n(moles number)=m(mass amount)/mW(molecular weight), so:

n(lidocaine)=m(lidocaine)/mW(lidocaine)= 1 g /234,34 g/mol~0,0043 mol.

Now we can calculate the equivalents.

Take in account that for sulfuric acid, de number of equivalents per mole is 2 (because of the double dissociation of the acid), while the number of equivalents per mole of lidocaine is 1.

Then we can conclude that:

0,0043 equivalents of lidocaine need 0,088 equivalents of sulfuric acid

1 equivalent of lidocaine need (0,088/0.0043)=20,46~20 equivalents of sulfuric acid

Finally, we can conclude that for the described procedure, 20 equivalents of sulfuric acid per equivalent of lidocaine are needed.

4 0

3 years ago

In your opinion, are scientists born or made? How can everyday people challenge or extend scientific ideas and make scientific

butalik [34]

Answer:

made

Explanation:

scientists are made-

7 0

4 years ago

Determine what mass of carbon monoxide and what mass of hydrogen are required to form 6.0 kg of methanol by the reaction CO(g) +

siniylev [52]

Answer:

5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.

Explanation:

The balanced reaction:

CO (g) + 2 H₂ (g) -> CH₃OH (l)

By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

CO: 1 mole
H₂: 2 moles
CH₃OH: 1 mole

Being the molar mass of each compound:

CO: 28 g/mole
H₂: 1 g/mole
CH₃OH: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CO: 1 mole* 28 g/mole= 28 grams
H₂: 2 moles* 1 g/mole= 2 grams
CH₃OH: 1 mole* 32 g/mole= 32 grams

Being 6 kg equivalent to 6000 grams (1 kg= 1000 grams), you can apply the following rules of three:

If by stoichiometry 32 grams of methanol are formed from 28 grams of carbon monoxide, 6000 grams of methanol are formed from how much mass of carbon monoxide?

$mass of carbon monoxide=\frac{6000 grams of methanol*28 grams of carbon monoxide}{32 grams of methanol}$

mass of carbon monoxide= 5250 grams= 5.25 kg

If by stoichiometry 32 grams of methanol are formed from 2 grams of hydrogen, 6000 grams of methanol are formed from how much mass of hydrogen?

$mass of hydrogen=\frac{6000 grams of methanol*2 grams of hydrogen}{32 grams of methanol}$

mass of hydrogen= 375 grams

5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.

8 0

3 years ago

What is the mass in grams of KBr in 0.400 L of a 0.350 M solution???

melamori03 [73]

Answer:

The answer to your question is: 16.7 g of KBr

Explanation:

Data

mass KBr = ? g

Volume = 0.400 L

Concentration = 0.350 M

Formula

Molarity = moles / volume

moles = molarity x volume

Process

moles = (0.350)(0.400)

= 0.14

MW KBr = 39 + 80 = 119 g

119 g of KBr -------------------- 1 mol

x -------------------- 0.14 mol

x = (0.14 x 119) / 1

x = 16.7 g of KBr

8 0

3 years ago

Read 2 more answers

You use energy to heat your home. What ultimately happens to the energy that you pay for in your heating bill?

Alekssandra [29.7K]

Answer:

1. The energy escapes your home and heats the outside.

Explanation:

4 0

4 years ago