Answer:
20.5 × 10²³ molecules of He
Explanation:
Given data:
Number of moles of He = 3.40 mol
Number of molecules of He = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 3.40 moles of He:
3.40 mol × 6.022 × 10²³ molecules
20.5 × 10²³ molecules of He
5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.
The mass per unit amount of a certain chemical entity is known as the molar mass (symbol M, SI unit kgmol1). The chemical entity in question should always be identified in accordance with the mole definition.
The number of atoms present in 1 mole of hydrogen is equal to 6.02 × 10²³ known as Avogadro’s number (NA).
The units of molar mass follow its definition; grams per mole. Mathematically, the defining equation of molar mass is
Molar mass = mass/mole = g/mol
180g/mol glucose has = 6.02 × 10²³
x g/mol glucose has = 1.90 × 10 ²²
To find x;
x = 5.6 × 10⁻³ g/mol
Therefore, 5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.
Learn more about molar mass here:
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Answer:
At the second equivalent point 200 mL of NaOH is required.
Explanation:
at the first equivalent point:
H2A + OH- = HA- + H2O
initial mmoles y*100 y*100 - -
final mmoles 0 0 y*100 y*100
at the second equivalent point:
HA- + OH- = A2- + H2O
initial mmoles y*100 y*100 - -
final mmoles - - y*100 y*100
at the second equivalent point we have that y*100 mmoles of NaOH or 100 mL of NaOH ir required, thus:
at the second equivalent point 200 mL of NaOH is required.
Answer:
its the 3rd option.
the molecules move from region of higher concentration to a region of lower concentration.
Explanation:
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