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lana66690 [7]
3 years ago
9

Powered ventilation systems should be turned on for how many minutes before starting the engine to ensure all gasoline vapors ha

ve been removed before ignition?
Physics
2 answers:
stepan [7]3 years ago
8 0

Answer:

Minimum of four minutes.

Explanation:

The essence of this is to avoid explosions by removing flammable gases due to reaction with sufficient oxygen. Evaporation of gasoline creates vapors or fumes that are denser than air which would settle to the bottom of a vessel and cause explosion if enclosed areas are not properly ventilated to remove the fumes.

Verizon [17]3 years ago
3 0
I really don’t undagaujsndwj
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Si uno de los valores de la tabla no se visualiza en el gráfico, ¿Cómo lo encontramos?
ivanzaharov [21]
No, no me habla espanol. yo soy ingles
6 0
2 years ago
A cart's initial velocity is +3.0 meters per second. What is its final velocity after accelerating at a rate of 1.5 m/s2 for 8.0
Katarina [22]

Answer:

V = 15m/s

Explanation:

Given the following data;

Initial velocity = 3m/s

Time = 8secs

Acceleration = 1.5m/s²

To find the final velocity, we would use the first equation of motion;

V = U + at

Substituting into the equation, we have

V = 3 + 1.5*8

V = 3 + 12

V = 15m/s

6 0
2 years ago
Is this statement true or false? Most metals in the chart react with<br> oxygen.
n200080 [17]

Answer:

true

Hoped this helped(⁄ ⁄>⁄ ▽ ⁄<⁄ ⁄)

7 0
3 years ago
A water pipe having a 4.00 cm inside diameter carries water into the basement of a house at a speed of 1.00 m/s and a pressure o
posledela

Answer:

8.16\ \text{m/s}

Explanation:

d_1 = Initial diameter = 4 cm

v_1 = Initial velocity = 1 m/s

d_2 = Final diameter = 7.8 m

v_2 = Final velocity

A = Area = \pi\dfrac{d^2}{4}

From the continuity equation we get

A_1v_1=A_2v_2\\\Rightarrow \pi\dfrac{d_1^2}{4}v_1=\pi\dfrac{d_2^2}{4}v_2\\\Rightarrow v_2=\dfrac{d_1^2}{d_2^2}v_1\\\Rightarrow v_2=\dfrac{4^2}{1.4^2}\times 1\\\Rightarrow v_2=8.16\ \text{m/s}

The speed of water at the second floor is 8.16\ \text{m/s}.

8 0
3 years ago
N2 + 3H2 mc033-1.jpg 2NH3
Svetradugi [14.3K]

N2+3H2->2NH3

When 3 moles of H2 react, they produce 2 moles of NH3

3 moles of H2 have a mass of 2.02 g

2 moles of NH2 have a mass of 17.0 g

So when 2.02 g H2 react, they produce 17.0 g NH3

If 26.3g H2 react with a yield of 100%, we expect…

2.02g H2_____17.0gNH3

26.3g H2_____x=221gNH3

So now let’s calculate the percentage:

221gNH3­­­­­­­­_________100%

79.0gNH3_________x=79.0*100/221=35.7%

3 0
3 years ago
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