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photoshop1234 [79]
3 years ago
10

You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther

mometer is in contact with boiling water. The boiling water is under regular atmospheric pressure. What is the temperature of the thermometer, when it reads a pressure of 500.0 kPa?
Physics
1 answer:
Travka [436]3 years ago
5 0

Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K

Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

T2 = T1 * (P2/P1)

T2 = (100 + 273) * (500 / 294)

T2 = 373 * (500 / 294)

T2 = 373 * 1.7

T2 = 634 K

T2 = 634 K - 273 K = 361° C

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Elan Coil [88]

Answer:

The horse is going at 12.72 m/s speed.

Explanation:

The initial speed of the horse (u) = 3 m/s

The acceleration of the horse (a)= 5 m/s^{2}

The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m

Applying the second equation of motion to find out the time,

s=ut+\frac{1}{2}at^{2}

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2.5t^{2}+3t-15.3=0

Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.

Now applying first equation of motion, to find out the final velocity,

v=u+at

v=3+1.945*5

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v=12.72 m/s

The horse travels at a speed of 12.72 m/s after covering the given distance.

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Hope this helps! I would greatly appreciate a brainliest! :)
3 0
3 years ago
Please help I will mark you brainliest
Radda [10]

I believe the answer is a

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1 D ,2 B ,5 C ,3 A ,4 E i dont know why you gotta have 20 words to answer it but yeah

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