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photoshop1234 [79]
3 years ago
10

You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther

mometer is in contact with boiling water. The boiling water is under regular atmospheric pressure. What is the temperature of the thermometer, when it reads a pressure of 500.0 kPa?
Physics
1 answer:
Travka [436]3 years ago
5 0

Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K

Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

T2 = T1 * (P2/P1)

T2 = (100 + 273) * (500 / 294)

T2 = 373 * (500 / 294)

T2 = 373 * 1.7

T2 = 634 K

T2 = 634 K - 273 K = 361° C

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while flying a plane parallel to the ground a pilot releases a fuel tank in order to reduce the planes mass. what is the tanks f
stepan [7]

La velocidad vertical del tanque después de caer 10 m es 14 m/seg .

La velocidad vertical del tanque se calcula mediante la aplicación de la fórmula de velocidad , la componente vertical Vfy, del movimiento horizontal como se muestra a continuación :

Vfy=?

  h = 10 m

                              Fórmula de Velocidad vertical Vfy:

                           Vfy²  = 2*g*h

                            Vfy= √(2*9.8m/seg2* 10m )

                            Vfy= 14 m/seg

7 0
3 years ago
What is a net force on an object that has a mass of 20.0 kg, an applied force of 100 n moving on a surface with a friction coeff
sergiy2304 [10]

The net force on the object as described is; 58.84N

Two forces acting on the object are;

  • The <em>applied force and the frictional force.</em>

In essence; the frictional force can be evaluated as;

  • Frictional force; = coefficient × Weight of object.

  • Frictional force = 0.21 × 20 × 9.8.

  • Frictional force = 41.16N

  • The Net force = Applied force - frictional force

  • Net force = 100 - 41.16N

Net Force = 58.84 N.

Read more:

brainly.com/question/94428

5 0
3 years ago
If you don’t know the answer please please don’t answer, I have to do this for a test and it’s 100 points
frutty [35]

Answer:

I believe that it's C

Explanation:

4 0
3 years ago
Read 2 more answers
An archer shoots an arrow at an 85.0 m distant target; the bulls eye of the target is at same height as the release height of th
inessss [21]

Answer:

  a) 14.1°

  b) over

Explanation:

The usual model of ballistic motion assumes that the only force on the flying object is that due to gravity. When an object is launched with initial velocity v0 at some angle θ with respect to the horizontal, the distance it travels is ...

  d = (v0)²sin(2θ)/g

Using this relation, we can find the launch angle to make the object travel a given distance:

  θ = 1/2arcsin(dg/v0²) . . . . where g is the acceleration due to gravity

__

<h3>a)</h3>

For the arrow to hit a target 85 m away at the same height it was launched with speed 42.0 m/s, the launch angle must be ...

  θ = 1/2arcsin(dg/v0²) = 1/2(arcsin(85·9.8/42²)) ≈ 14.0893°

The arrow must be released at an angle of about 14.1°.

__

<h3>b)</h3>

The flight time to the tree at a distance of 42.5 m will be that distance divided by the horizontal speed:

  t = 42.5/(42cos(14.0893°)) ≈ 1.0433 . . . . seconds

The height at that time is ...

  h(t) = -4.9t² +42sin(14.0893°)t ≈ 5.33 . . . meters

The arrow will go <em>over</em> the branch.

_____

<em>Additional comment</em>

Since gravity provides the only force on the arrow, its horizontal speed is constant at vh = v0·cos(θ), when the arrow is launched with speed v0 at angle θ above the horizontal. Its vertical speed will be reduced by the acceleration of gravity, so will be vv = v0·sin(θ) -gt. The height is the integral of the vertical speed, so is ...

  h(t) = (1/2)gt² +v0·sin(θ)t

The height will be 0 at t=0 and at t=2v0sin(θ)/g, so the horizontal distance traveled will be ...

  d = vh·t

  = (v0·cos(θ))(2v0·sin(θ)/g) = (v0²/g)(2·sin(θ)cos(θ))

  = v0²sin(2θ)/g

Note that this is all simplified by the fact that the target and launch point are at the same level (h=0).

6 0
3 years ago
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 275 N in the positive x di
Volgvan

Answer:

f = 347.08 N

Explanation:

The frictional force exerted by the floor on the refrigerator is given as follows:

f = \mu R = \mu W

where,

f = frictional force = ?

μ = coefficient of static friction = 0.58

W = Weight of refrigerator = mg

m = mass of refrigerator = 61 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

f = \mu mg\\f = (0.58)(61\ kg)(9.81\ m/s^2)\\

<u>f = 347.08 N</u>

8 0
3 years ago
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