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3 years ago

What kind of energy is stored when you squeeze a mattress?

2 answers:

7 0

Answer: When you squeeze a mattress, and you release it, you can see that return to the original shape. So, when you are squeezing it, the mattress "want" to return to the original shape. The mattress does it by storing elastic energy, and when you stop squeezing it, uses the elastic energy to return to the original shape.

so the energy stored is elastic energy.

yuradex [85]3 years ago

4 0

Elastic Energy is stored in it.

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Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration wo

Nina [5.8K]

Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy ) ---- ( 1 )

where :

work done = p * t

= 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2 given ; m = 1200 kg and initial V = 0

back to equation 1

473040000 * 10^6 = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

i) Determine how fast the rocket is ( acceleration of the rocket )

a = Vf / t

= 887918.92 / ( 1 year )

= 0.0282 m/s^2

ii) determine distance travelled by rocket

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) = Vf^2 / ( 2a )

= ( 887918.92 )^2 / ( 2 * 0.0282 )

= 13.98 * 10^12 m

8 0

3 years ago

Water waves, earthquake waves, sound waves, and the waves that travel down a rope or spring are all examples of what waves.

Margaret [11]

Compression waves :-)

5 0

3 years ago

22. Sweat glands are found in human skin. These glands release sweat to help the body cool during exercise. What would MOST LIKE

Bingel [31]

Answer:

Explanation:

all i know is that sweat keeps your body from overheating

7 0

3 years ago

You are on your balcony and notice some bad squirrels digging in your garden directly below. You start tossing your pistachios a

Rashid [163]

Answer:

0.43 s

Explanation:

We have the following parameters:

Initial velocity, u = 7.4 m/s

Acceleration of gravity, g = 9.8 $m/s^2$

Distance, s = 43 in + 10 ft = 1.092 m + 3.048 m = 4.14 m

Time, t = ?

Using the equation of motion $s=ut +\frac{1}{2}gt^2$ , we have

$4.14 = 7.4t + 0.5\times9.8t^2$

$4.9t^2 + 7.4t - 4.14 =0$

Using the quadratic formula $\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ where a = 4.9, b = 7.4 and c = - 4.14, and solving for the positive value of t only, we have

$t = 0.43$ s

3 0

4 years ago

EASY BRAINLIEST PLEASE HELP!!

Rudiy27

Answer:

I think the awnser is B (but don't qoute me on that) if its right then yay but if its wrong im sorry

Explanation:

5 0

3 years ago

Read 2 more answers