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V125BC [204]
3 years ago
5

Why does light of a certain frequency need to be used to produce a current in the photoelectric effect?

Physics
1 answer:
olchik [2.2K]3 years ago
3 0
The reason to why does light of a certain frequency need to be used to produce a current in the photoelectric effect is <span>A. The frequency of light must be the same as the frequency of vibration of the atoms in the substance to cause a current.</span>
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blondinia [14]
Buffers neutralize the acid and the bases
7 0
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A 150 g egg is dropped from 3.0 meters. The egg is
Lynna [10]

<u><em>Answer:</em></u>

<u><em> </em></u>

<u><em>9.2 N, with significant figure rounding (2 s.f.) </em></u>

<u><em></em></u>

<u><em>Explanation:</em></u>

<u><em>This problem can be solved using momentum. The following equation relates momentum (mass & velocity) with force and time:</em></u>

<u><em></em></u>

<u><em>Note that  where v is the final velocity and v₀ is the initial velocity. Δv just means change in velocity.</em></u>

<u><em></em></u>

<u><em>Mass of the egg is 150 g, but we need to convert to kilograms if we want to use Newtons as a unit. 150 g is equal to 0.15 kg. since 1000 g = 1kg. </em></u>

<u><em>m = 0.15 kg</em></u>

<u><em></em></u>

<u><em>The dropped from 3.0 meters is irrelevant as the question tells us the initial velocity of the egg: 4.4 m/s before it hits the ground.</em></u>

<u><em>v₀ = 4.4 m/s [down]</em></u>

<u><em></em></u>

<u><em>When it comes to a stop, the egg will have a velocity of 0.</em></u>

<u><em>v = 0 m/s</em></u>

<u><em></em></u>

<u><em>The time it takes for the egg to stop is 0.072 seconds.</em></u>

<u><em>Δt = 0.072 s</em></u>

<u><em></em></u>

<u><em>Therefore, if down is positive, then</em></u>

<u><em></em></u>

<u><em>   </em></u>

<u><em></em></u>

<u><em>We round to two significant figures since every quantity has two sig. figs.</em></u>

<u><em>We only care about the magnitude, not direction. The answer is 9.2 N.</em></u>

<u><em>Unlimited, ad-free access to all of the questions with Brainly Plus</em></u>

<u><em>START 7 DAY FREE TRIAL</em></u>

<u><em>Click to let others know, how helpful is it</em></u>

<u><em>5.0</em></u>

5 0
3 years ago
What happens to ar object in free fall?​
Inessa05 [86]
Energy from the gravitational potential store in converted to kinetic energy. Air friction acts against the object, dissipating some energy as heat or sound. The object will continuously accelerate until the acceleration is equal to the air friction acting against it. This is when it reaches terminal velocity
5 0
3 years ago
1)why do we get electric shock while holding a live wire barefooted and not when wearing rubber shoes?
katrin2010 [14]
Electricity is always going to take the path of least resistance to ground. The rubber in your shoes is not a conductor of electricity, therefore you are not completing the circuit and you don't get shocked. Your bare feet, on the other hand ARE conductors of electricity, so when you hold the wire, you complete the circuit and become the path of least resistance to ground... ZAP!
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3 years ago
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o
Margarita [4]

Answer:

V_{average} = \frac{1}{2}  V_o  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = \left \{ {{V=V_o \ \ \  t<  \tau /2} \atop {V=0 \ \  \ \  t> \tau /2 }   } \right.

to substitute in the equation let us separate the into two pairs

             V_average = \int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt

             V_average = V_o \ \int\limits^{1/2}_0 {} \, dt

             V_{average} = \frac{1}{2}  V_o

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

6 0
3 years ago
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