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andrew-mc [135]
4 years ago
14

If a solution containing 51.429 g of mercury(ii) perchlorate is allowed to react completely with a solution containing 16.642 g

of sodium sulfate, how many grams of solid precipitate will be formed?
Chemistry
1 answer:
OLga [1]4 years ago
7 0
Hg(No3)2  +NaSO4   --->2NaNO3  +  HgSO4(s)
calculate  the moles  of   each  reactant
moles=mass/molar  mass

moles of  Hg(NO3)2=  51.429g/  324.6  g/mol(molar  mass  of  Hg(NO3)2)=0.158  moles

moles Na2SO4  16.642g/142g/mol=  0.117  moles  of  Na2SO4

Na2SO4  is  the  limiting  reagent in  the   equation   and  by  use  mole  ratio  Na2So4  to  HgSO4  is  1:1   therefore  the  moles  of  HgSO4  =0.117  moles

mass  of  HgSO4=moles  x  molar   mass  of  HgSo4=  0.117 g x  303.6g/mol=  35.5212  grams

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19.The Alkali and Alkaline Earth metals belong to which columns, respectively?
Morgarella [4.7K]

Answer:

i think it is d hope this helps

6 0
3 years ago
H2(g)+I2(g)→2HI(g)would not be affected by the addition of which gas?
denpristay [2]

Based on Le Chatelier's principle, the following factors will affect the chemical equilibrium

1) Temperature

2) Pressure

3) concentration

4) catalyst

The given equilibrium involves

H2(g) + I2(g) → 2HI(g)

The reactants are H2 and I2 while the product is HI. The equilibrium will be affected by changes in the concentration of H2, I2 or HI.

However, the equilibrium will not be affected by the addition of N2 since it is not involved in the reaction

Ans (c)


7 0
4 years ago
Which of the following elements has the smallest atomic radius
babunello [35]

Answer:

Element with the smallest radius is Carbon.

Explanation:

In a periodic table, atomic radius increases down the group due to addition of a new shell and decreases across the period from left to right due to increasing nuclear charge.

Due to addition of more electrons in same shell and increase of positive charge in nucleus increases attractive forces between electrons and nucleus hence decreasing size.

Carbon and Lithium are present in same period and hence Carbon has smaller size; Potassium and Bromine are present in same period and hence out of the two, Bromine has smaller size.

On comparing Carbon and Bromine, atomic radius increases down the group hence, Carbon has the smallest radius among the four given elements.

3 0
4 years ago
At a certain temperature this reaction follows first-order Kinetics with a rate constant of 0.0660
Juli2301 [7.4K]

Answer:

After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M.

Explanation:

Based on the reaction of the problem, you have as general kinetic law for a first-order reaction:

ln[HI] = -kt + ln [HI]₀

<em>Where [HI] is actual concentration after time t, </em>

<em>k is rate constant </em>

<em>and [HI]₀ is initial concentration of the reactant. </em>

Initial concentration of HI is 0.310M,

K is 0.0660s⁻¹,

And the actual concentration is 0.0558M:

ln[HI] = -kt + ln [HI]₀

ln[0.0558M] = -0.0660s⁻¹*t + ln [ 0.310M]

-1.7148 = -0.0660s⁻¹*t

26.0s = t

<h3>After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M</h3>

<em />

3 0
3 years ago
Write a balanced chemical equation, including physical state symbols, for the decomposition of liquid nitroglycerin () into gase
Marat540 [252]

Answer:

4C3H5N3O9 (l)  ---------> 12CO2 (g)  +  H20 (g)  + 6N2 (g) + 6O2 (g)

Explanation:

Nitroglcerin is a drug basically used to treat chest pain. It is a dense, colourless and explo9sive liquid. Its molecular formula is C3H5N3O9.

It decomposes to gaseous dinitrogen, gaseous dioxygen, gaseous water and gaseous carbon di oxide

The equation for its decomposition is shown below;

4C3H5N3O9 (l)  ---------> 12CO2 (g)  +  H20 (g)  + 6N2 (g) + 6O2 (g)

3 0
4 years ago
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