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sineoko [7]
3 years ago
15

Which of the following must be true about the object labeled X in the circuit below?

Physics
1 answer:
Alex787 [66]3 years ago
4 0

the answer is c and if I help you  thank me
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Three materials, put them in order of what
Grace [21]

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it's a

Explanation:

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Is space expanding within clusters of galaxies? why or why not?
GarryVolchara [31]

No, since their gravity is powerful enough to keep them together even while the universe expands as a whole. Space is not expanding within clusters of galaxies.

<h3>What is a galaxy?</h3>

A galaxy is a massive clump of gas, dust, and billions of stars and their solar systems bound together by gravity.

No, since their gravity is powerful enough to keep them together even while the universe expands as an entire.

Hence,space is not expanding within clusters of galaxies.

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brainly.com/question/2905713

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2 years ago
Why is the restoring force in Hooke's law a negative value?
Rudiy27
It's a negative value because the negative sign on the spring's force means the force exerted opposes the spring's displacement
8 0
3 years ago
Read 2 more answers
Which of the following BEST describes what occurs in a fusion reaction?
Greeley [361]

Answer:

Two mass nuclei are joined to form one nucleus

Explanation:

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4 0
3 years ago
El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La
allsm [11]

Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta

En donde:

\omega_{f}: es la velocidad angular final =  2000 rpm = 209,4 rad/s

\omega_{0}: es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.  

Resolviendo la ecuación (1) para α, tenemos:

\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}  

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.  

b) El tiempo transcurrido se puede encontrar como sigue:

\omega_{f} = \omega_{0} + \alpha t

Resolviendo para t, tenemos:

t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

3 0
3 years ago
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