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s2008m [1.1K]
3 years ago
7

An upward force act on a proton as it moves with a speed of 2.0 x 10^5 meters/seconds through a magnetic field of 8.5 x 10^2

Physics
1 answer:
Gekata [30.6K]3 years ago
7 0

Force on a moving charge is given by formula

\vec F = q(\vec v \times \vec B)

here we know that this force will be maximum when velocity is perpendicular to magnetic field

\vec F = qvB

here we know that

v = 2.0 \times 10^5 m/s

q = 1.6 \times 10^{-19} C

B = 8.5 \times 10^2 T

now we have

F = (1.6 \times 10^{-19})(2 \times 10^5)(8.5 \times 10^2)

F = 2.72 \times 10^{-11} N

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