The answer for the following question is explained.
<u><em>Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is</em></u><u> </u><u><em>one(1).</em></u>
Explanation:
Here;
n represents the principal quantum number
l represents the Azimuthal quantum number
m represents magnetic quantum number
s represents spin quantum number
n = 5,
l = 2,
m = -2,
s = +1/2
Here, it implies 5d orbital.
In the 5d orbital, 10 electrons.
As the magnetic quantum number is -2, and so it can have 1 electron.
<u><em>Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is</em></u><u> </u><u><em>one(1)</em></u>
Answer:
the moluculer formula is the answer
Explanation:
nuclear power--used to turn turbines...
fossil fuels--burned to provide energy that is....
renewable energy--energy that with come back after use
outlet--a device....
steam--nuclear reactors....
I'm not sure but I tried lol,lemme know if I'm wrong :D
Answer:
Second element(Titanium); [Ar] 3d2 4s2
Third element(Vanadium):Ar 3d3 4s2
Explanation:
Given that there are only three d orbitals in universe L instead of five, the electronic configuration of the second and third elements in the first transition series will now look thus;
Second element(Titanium); [Ar] 3d2 4s2
Third transition element(Vanadium):Ar 3d3 4s2
Hence, the electronic configuration of Titanium and Vanadium in universe L is just the same as what it is on earth.