Explanation: Oxygen plays a very vital role in the life of aquatic animals. The dissolved oxygen in the water helps them to breathe under water.
Optimum level of oxygen for deep living animals like oysters, bottom feeders, crabs is around (1-6 mg/L), while the animals living on the upper side like fishes require a higher amount of around (4-6 mg/L).
If the oxygen concentration in the pond is not optimum, there will no aquatic life and hence, the ecosystem will be affected.
Hence, oxygen concentration affects the fishes that live in the pond to a higher extent.
C: 8 I’m pretty sure, I did partly the problem and that’s what I got! if correct pls heart this
The answer is (3) 0.193M. To find the molarity of HNO3, you just need to use the M1V1=M2V2 equation (no need to worry about ionization constants because HNO3 is monoprotic and KOH dissociates 1:1). Since the molarity you are looking for is M1, you get M1=M2V2/V1=(0.150)(32.1)/25.0= 0.193M
2KCIO3=2KCL+302
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Mg+2HCl------- MgCl2 +H2
2 moles ofHCl use 1 mole of Mg
3.91 mol of HCl=1/2 *3.91
Moles of Mg used = 1.955 moles
Moles of HCl used=3.91 mol
1 mole of Mg make 1 mole of MgCl2
So moles of MgCl2=1.955 moles
Molar mass=24+ (35.5*2)
Molar mass= 95 g/ mol
Mass of MgCl2 produced=moles *molar
