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Nimfa-mama [501]
3 years ago
8

50 gramos de soluto a temperatura ambiente en un recipiente de 100ml de agua, pero el solito se acumulaba en el fondo. La calent

ó lo que le permitió disolver solo 10 gramos adicionales de soluto. Que solución obtuvo? Sobresaturada, instaurada, saturada o diluida
Chemistry
1 answer:
Sveta_85 [38]3 years ago
6 0

Answer:

  • <u><em>Saturated</em></u>

<u><em></em></u>

Explanation:

Translation:

  • <em>50 grams of solute at room temperature in a 100ml container of water, but the solute accumulated at the bottom. He heated it allowing it to dissolve just an additional 10 grams of solute. What solution did you get? Oversaturated, unsaturated, saturated or diluted</em>

<em />

<h2>Solution</h2>

A<em> saturated</em> <em>solution</em> contains the maximum amount of solute that it can dissolve at the given temperature and pressure.

If you add more solute than that it will not get <em>dissolved</em> but the extra solute will remain as a solid at the<em> bottom</em> of the <em>solution</em>.

The fact that, for the <em>solution</em> with 50 grams of solute, the <em>solute accumulated</em> at the <em>bottom</em> means that it could not dissolve more, so the solution was saturated.

By <em>heating</em> the solution it was able to <em>dissolve</em> more <em>solute </em>but the fact that yeat some <em>grams</em> were undissolved means that the solution was still saturated at the new temperature.

<em>Oversaturated</em> is an unstable state at which the solution can dissolve more solute than what the normal solubility permits. That state can be reached only under special procedures which would require a different description.

Thus, you get a <em>saturated solution</em>.

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Consider the reversible reaction, A+B⇌C+D. If the concentration of product D is increased, the rate of the reverse reaction woul
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If the concentration of product D is increased, the rate of the reverse reaction would increase.

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A + B ⇄ C + D

In given condition the equilibrium is disturb by increasing the concentration of product.

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4 0
3 years ago
Which of the following you is true for a limiting reactant
skad [1K]

Answer:

  • <em><u>C) The limiting reactant has the lowest ratio of moles available / coefficient in the balanced equation.</u></em>

Explanation:

Please, find attached a complete question to determine which of the statements is or are true for a limiting reactant in a chemical equation.

First, remember that the limiting reactant is the substance that is consumed completely while the excess reactant is the substance that does not react completely.

The limiting reactant is found comparing the stoichiometry ratio and the actual ratio between the reactants.

The stoichiometry ratio is found using the coefficientes of the chemical equation.

For illustration, assume the general chemical equation:

         aA+bB\rightarrow cC+dD

The stoichiometric ratio of the reactants is:

          a\text{ }moles\text{ }of\text{ }A/b\text{ }moles\text{ }of\text{ }B

If the ratio of the available moles of substance A to the available moles of  substance B is greater than the stoichiometric ratio, it means that there are more moles of the substance A than what is needed to react with the available moles of substance B, then A will be in excess and B will B the limiting reactant.

If, on the contrary, the ratio of the available moles of substance A to the available moles of  substance B is is less than the stoichiometric ratio, then substance A is less than the necessary to make the all the moles of substance B react, meaning that the substance A will limit the reaction (it will be consumed completely), while the substance B will be in excess.

As for the options:

<em><u>A) The limiting reactant is has the lowest coefficient in a balanced equation.</u></em>

This is false, since it is not the magnitude of the coefficiente what determines the limiting reactant, but the comparison of the ratios.

<u><em>B) The limiting reactant is the reactant for which you have the fewest number of moles.</em></u>

This is false because it is not the number of moles what determines the limiting reactant , but the comparison of the ratios.

<u><em>C) The limiting reactant has the lowest ratio of moles available / coefficient in the balanced equation.</em></u>

This is true as proved below.

The stoichiometric ratio of the reactants is:

          a\text{ }moles\text{ }of\text{ }A/b\text{ }moles\text{ }of\text{ }B

The actual ratio is:

         available\text{ }moles\text{ }of\text{ }A/available\text{ }moles\text{ }of\text{ }B

Assume the first ratio is less than the second (which describes when the substance A is in excess and the limiting reactant is the substance B).

a\text{ }moles\text{ }of\text{ }A/b\text{ }moles\text{ }of\text{ }B

Change the relation to show the ratios of moles available of each substance to the cofficient in the chemical equation:

available\text{ }moles\text{ }of\text{ }B/b\text{ }moles\text{ }of\text{ }B

Then, in the scenary that the limiting reactant is the substance B, the ratio of the left is lower than the ratio of the right, which is the same that limiting reactant has the lowest ratio of moles available / coefficient in the balanced equation.

<em><u>D) The limiting reactant has the lowest ratio of coefficients in the balanced eqution/moles available.</u></em>

<em><u /></em>

This ratio is the inverse of the ratio of the previous statement, thus the relation is inverse, and, since the previous statement was true, this statement is false.

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