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jolli1 [7]
3 years ago
12

Write a paragraph in your science journal that explains why you can step out of the shower into a warm bathroom and begin to shi

ver?
Chemistry
1 answer:
Fiesta28 [93]3 years ago
7 0
Just you think about it, a shower with hot water, you step out and it is cold, this happens because you have a enclosed space with the heat, so you get use to the heat, you step out it is cold. Hope this helped!
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The colour of light depends on it's wave length.Red light have a wave length in the order of 7.8*10 raise to power of -7metre, e
Arisa [49]
That will be 0.78*10 raise to the power of -1 nanometers
8 0
3 years ago
According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. A 150-lb
julsineya [31]

Answer:

The density of the swimmer is 0.0342 lbm/in3.

This value makes sense as the density of the body is very similar to the water.

Explanation:

If the swimmers is floating, the weight of the swimmer must be equal to the upward buoyant force.

We can express the weight force as the product of density and volume of the swimmer.

Then

\rho_{swimmer}*V_{swimmer}=\rho_{water}*V_{water_displaced}\\\\\rho_{swimmer}*V_{swimmer}=\rho_{water}*0.95**V_{swimmer}\\\\\rho_{swimmer}=0.95*\rho_{water}\\\\\rho_{swimmer}=0.95*0.036 lbm/in3\\\\\rho_{swimmer}=0.0342lbm/in3

It makes sense as the density of the body is very similar to the water.

5 0
3 years ago
What does the group number of element 114 have to do with its stability?
zhenek [66]

Answer:

Super-heavy elements like 114 usually only exist for fractions of a second. ... The physicists called these magic numbers the “island of stability”, because the elements with the numbers cluster together on the periodic table, flanked on all sides by ephemeral elements that dissipate in nanoseconds.

8 0
3 years ago
What is co-wolent bond?<br><br>​
alex41 [277]

Answer:

Explanation:

This is a bond with reacts with metal's

7 0
3 years ago
How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
Alona [7]

Answer:

Approximately 1.95 \times 10^{2}\; \rm J.

Explanation:

Look up the specific heat of gaseous neon:

c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}.

Calculate the required temperature change:

\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Let m denote the mass of a sample of specific heat C. Energy required to raise the temperature of this sample by \Delta T:

Q = c \cdot m \cdot \Delta T.

For the neon gas in this question:

  • c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}.
  • m = 10.6\; \rm g.
  • \Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Calculate the energy associated with this temperature change:

\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}.

3 0
3 years ago
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