Transparent - when light is in context with transparent materials almost all of the the light is allowed to go through these materials.
Ex: glass
Translucent- materials that do not allow light to pass through easily.
Ex: tissue paper
Opaque- materials that allow no light to go through them .
Ex: wood
Answer:
m(Na3AlF6)=57.6537 kg. Leftover mass will be 52.8644 kg
Explanation:
Al2O3(s)+6NaOH(l)+12HF(g)⟶2Na3AlF6+9H2O(g)
n(Al2O3)=m(Al2O3)/M(Al2O3)=14000/101.96=137.31 mol
n(NaOH)=m(NaOH)/M(NaOH)=59400/40=1485 mol
n(HF)=m(HF)/M(HF)=59400/20.01=2968 mol
To know what is in excess we divide moles by coefficients and compare numbers.
n(Al2O3) = 137.31 mol
n(NaOH)/6=247.5 mol
n(HF)/12=247.33 mol
so NaOH and HF are in excess
So
m(Na3AlF6)=n(Na3AlF6)*M(Na3AlF6)/1000=n(Al2O3)*2*M(Na3AlF6)/1000=57.6537 kg.
Leftover mass will be (n(NaOH)-n(Al2O3)*6)*40 + (n(HF)-n(Al2O3)*12)*20.01=26445.6+26418.8=52864.4 g= 52.8644 kg
Mg3N2 + 6H2O => 3Mg(OH)2 + 2NH3
Tin is an element called Stannum and has the symbol Sn. Molar mass is the mass of 1 mol of a compound, 1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up an element or molecules making up a compound.
While the number of atoms making up 1 mol is the same for any element, the weight of 1 mol of substance varies from one another.
In tin(Sn) molar mass - 118.71 g/mol
In 118.71 g - there's 1 mol of tin
therefore in 37.6 g of tin - 1 x 37.6 / 118.71 = 0.31 mol
In 37.6 g of tin, there's 0.31 mol
Answer: it reacts with the alkali metals (M) to form a salt MX, where X is the halogen.
Explanation: Group 7A elements are halogen and they react with alkali metals like Sodium or potassium to form a salt like NaCl