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Aliun [14]
3 years ago
14

The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to form its co

njugate, and the other half still remains unreacted. If 0.580 moles of a monoprotic weak acid (Ka = 4.5 _ 10-5) is titrated with NaOH, what is the pH of the solution at the half-equivalence point?
Chemistry
1 answer:
kirill [66]3 years ago
5 0
The only thing you need to know to find  pH of the solution at the half-equivalence point is to remember that  pH is always equal to pKa, therefore you can easily get ehat you need - <span>4.35.</span>
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When pellets of NaOH(s) are added to a flask of water, it is observed that the temperature of the water increases as the pellets
Nataly [62]

Answer: It is an exothermic process because heat energy is absorbed by the water as the NaOH(s) dissolves in it.

Explanation:

Endothermic reaction : It is a type of chemical reaction where the energy is absorbed from the surrounding. In the endothermic reaction, the reactant are less than the energy of product. In endothermic reaction, the change in enthalpy is, positive

Exothermic reaction : It is a type of chemical reaction where the energy is released into the surrounding. In the exothermic reaction, the energy of reactant are more than the energy of product. In exothermic reaction, the change in enthalpy is, negative.

Thus as energy is absorbed by water, which has been released by NaOH, the process is exothermic.

3 0
3 years ago
If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)
Ludmilka [50]

Answer:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln}    *100\%\\\\w/w\%=3.15\%

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

Regards.

4 0
3 years ago
Thinking and questioning is the start of the scientific inquiry process. Please select the best answer from the choices provided
aev [14]
Yes thats true! You always have to think about the question or project before you start a science experiment! :) 




8 0
3 years ago
Read 2 more answers
What is the pOH of<br> a<br> 2.6 x 10-6 M H+ solution?
scZoUnD [109]

Answer:

pH = -log 2.6 x 10-6 M

pH = 5.585

pOH= 14 - 5.585 = 8.415

8.4 as 2 sig figs

8 0
3 years ago
A solution of sodium iodide is added to a solution of potassium nitrate to make a potassium iodide precipitate and a sodium nitr
stich3 [128]

Answer:

NaNO3

Explanation:

Sorry If its incorrect

4 0
3 years ago
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