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3 years ago

Define transparent ,translucent ,opaque materials?

2 answers:

5 0

Transparent - when light is in context with transparent materials almost all of the the light is allowed to go through these materials.
Ex: glass

Translucent- materials that do not allow light to pass through easily.
Ex: tissue paper

Opaque- materials that allow no light to go through them .
Ex: wood

patriot [66]3 years ago

3 0

A transparent material is a material that

allows you to see right through it.

For example, glass is usually a transparent material.

A translucent material is a material that allows

you to see light, but it's distorted.

For example, tracing paper is a translucent material.

If a material is opaque, it blocks light from going through them.

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When table salt (NaCl) is added to water, it lowers the freezing point is more salt is added, the freezing point decreases even

AleksAgata [21]

The answer to the question is B

7 0

3 years ago

A 27.5 −g aluminum block is warmed to 65.9 ∘C and plunged into an insulated beaker containing 55.5 g water initially at 22.1 ∘C.

Wittaler [7]

Answer:

The final temperature of aluminium ≈ 26.32 °C

Explanation:

Step 1: explain the problem

A 27.5 −g aluminum block is warmed to 65.9 ∘C and plunged into an insulated beaker containing 55.5 g water initially at 22.1 ∘C.

Step 2: Data given

We will use the formule : Q = mcΔT

with Q = heat transfer ( J)

with m = mass of the substance (g)

with c = specific heat ( J/g °C)

with ΔT = change in temperature ( in °C or K)

mass of aluminium = 27.5g

mass of water = 55.5g

specific heat of aluminium = 0.900J/g °C

specific heat of water = 4.186 J/g °C

initial temperature of aluminium T1= 65.9 °C

initial temperature of water T1 = 22.1 °C

final temperature of water and aluminium = TO BE DETERMINED

Step 3: Calculate the initial temperature

To find the final temperature, we have to use the following formule:

-(Mass of aluminium) * (caluminium)*(ΔT)) = (Mass of water) *(cwater)*(ΔT)

-27.5g (0.900)(T2 - 65.9) = 55.5g (4.184j/g °C) (T2- 22.1)

-24.75*(T2-65.9) = 232.212 *(T2-22.1)

-24.75T2 + 1631.025 = 232.212T2 -5131,8852

-256.962 T2 = -6762.9102

T2 = 26.32 °C

The final temperature of aluminium ≈ 26.32 °C

6 0

3 years ago

500 mL solution of calcium chloride with a concentration of 0.75 mol/L. The mass of solute needed to make this solution is ___ _

BabaBlast [244]

Answer:

41.63g

Explanation:

Given parameters:

Volume of CaCl₂ = 500mL = 0.5L

Concentration = 0.75mol/L

Unknown:

Mass of the solute needed = ?

Solution:

The mass of the solute can be derived using the expression below;

Mass = number of moles x molar mass

But,

Number of moles = Concentration x Volume

So;

Mass = Concentration x Volume x molar mas

Molar mass of CaCl₂ = 40 + 2(35.5) = 111g/mol

Mass = 0.75 x 0.5 x 111 = 41.63g

5 0

3 years ago

Is the following a chemical or physical

Usimov [2.4K]

Explanation:

Chemical .
As you can't get sodium or chloride back from sodium chloride.
Sodium chloride is a ionic compound so the bonding is too hard to break .

There are two types of reactions

Physical
Chemical

6 0

3 years ago

it is method used to separate particulates from a liquid by allowing in the solids to settle at the bottom of the mixture

wariber [46]

Answer:

Decantation

Explanation:

Decantation is one of the process of separating mixture containing solid and liquid. In this process, gravity plays a very important role. The solid part of the mixture is allowed to settle down. The liquid is removed and separated in another container. It is a process that helps in the purification of the liquid. The particles that are insoluble settles down and is further subject to be separated from the mixture.

5 0

3 years ago