Answer:
You need the Delta H fusion for water. Multiply that by 50 grams. Then multiply 50 g x 4.184 x 65 to get joules to raise water to 65 degrees. Add these values together to get total joules.
Explanation:
Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.
Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.
Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.
Let the molar solubility be S upon dissociation.
PbBr₂ or Lead Bromide dissociates in pure water as follows:
PbBr₂ ----------> Pb⁺² + Br⁻
S 2S
Ksp = [Pb⁺²] [ Br⁻]
Ksp = (S) (2S)²
Ksp = 4S³
6.60 × 10⁻⁶ = 4S³
S = 0.0118M
Hence, the Molar solubility S is 0.0118M.
Learn more about Molar solubility here, brainly.com/question/16243859
#SPJ4
Answer:
Explanation:
Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32
Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32
Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .
Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :
94.78 g , 75.84 g , and 113.76 g
Their ratio = 94.78 : 75.84 : 113.76
divide them by 19
their ratio = 5 : 4 : 6
So these data are consistent with law of multiple proportion.
Answer: water and other small molecules
Explanation: the walls of the glomerulus is semipermeable permitting only the passage of water and other small molecules like, mineral salts, amino acids, glucose, urea. Large molecules like plasma protein, Platelets does not pass through the membrane.
Answer:
D.) The nuclear model describes the atom as a dense, positive nucleus surrounded by a cloud of negative electrons.