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Alja [10]
2 years ago
8

Define transparent ,translucent ,opaque materials?

Chemistry
2 answers:
zlopas [31]2 years ago
5 0
Transparent - when light is in context with transparent materials almost all of the the light is allowed to go through these materials.
Ex: glass

Translucent- materials that do not allow light to pass through easily.
Ex: tissue paper

Opaque- materials that allow no light to go through them .
Ex: wood
patriot [66]2 years ago
3 0

A transparent material is a material that

allows you to see right through it.

For example, glass is usually a transparent material.

A translucent material is a material that allows

you to see light, but it's distorted.

For example, tracing paper is a translucent material.

If a material is opaque, it blocks light from going through them.

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Chlorine forms a number of oxides with the following oxidation numbers: 1, 3, 4, 6, and 7. These compounds are stable and neutra
SashulF [63]

Answer:

Cl_2O, Cl_2O_3, ClO_2, ClO_3, Cl_2O_7

Explanation:

Empirical formula of the compound is the simplest ratio of elements present in the compound.

Empirical formula of compounds of chlorine with oxygen is as follows:

Compounds in which oxidation state of Cl is +1

Cl_2O

Compounds in which oxidation state of Cl is +3

Cl_2O_3

Compounds in which oxidation state of Cl is +4

ClO_2

Compounds in which oxidation state of Cl is +6

ClO_3

Compounds in which oxidation state of Cl is +7

Cl_2O_7

8 0
3 years ago
2NaCl + F2 yields 2NaF + Cl2
bearhunter [10]
Study your experiment setup.<span> In 30 minutes, how will the air temperature in the bottles compare?</span><span> What do you predict will happen to the ice in each bottle?</span>
7 0
2 years ago
I need help with this question please someone tell me the answer for this
Andrej [43]
Aueyeowosy yo this is my answer

5 0
2 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
1 year ago
Please help me with my science thank you!
Tatiana [17]
I cant see it maybe post it again?
4 0
2 years ago
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