Answer:
The Trout will have to jump 49 cm in order to catch the insect
Step-by-step explanation:
Here, we want to calculate the distance the Trout has to jump in order to catch the Insect
To calculate this, we need to know the difference in the distances
From what we have, the Trout is 32 cm below the surface while the Insect is 17 cm above the surface of the lake
The difference in height which will represent the distance that the Trout has to jump to catch the insect will be ;
17 + 32 = 49 cm
The LCD for 3/10,20/25,and 18/75 is 150
The two quadrilaterals are given similar .
In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .
The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC
We can form a proportion with the proportional sides:

To solve for x we cross multiply
12x=(16)(18)
12x=288
Dividing both sides by 12 we get
x=24.
The second longest side of quadrilateral EFGH is 24 ft.
Hello,
Answer A
s(x)=3x-7
s(2t-4)=3*(2t-4)-7=6t-12-7=6t-19