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Schach [20]
3 years ago
12

How could you find the y-coordinate of the midpoint of a vertical line segment with endpoints at (0,0) and (0,-12)

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0
I think it should be -6, because line segment equals 12 and it's midpoint will be 12/2 = 6, so you must go down by 6 from (0,0) point on y axis which is 0-6=-6

So the point will be (0, -6) 
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Answer:

y²=4√2.x

Step-by-step explanation:

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The distance between the focus and the directrix of the parabola P is

\frac{ |0-4| }{\sqrt{(1)^{2}+(-1)^{2}  } }=\frac{4}{\sqrt{2} }

{Since the perpendicular distance of a point (x1, y1) from the straight line ax+by+c =0 is given by \frac{ |ax1+by1+c| }{\sqrt{a^{2}+b^{2}  } } }

Let us assume that the equation of the parabola which is congruent with parabola P is y²=4ax

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Hence, the distance between focus and the directrix is 2a = \frac{4}{\sqrt{2} }, {Two parabolas are congruent when the distances between their focus and the directrix are same}

⇒ a=√2

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3 years ago
I need to know what is 18f=-216
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2 years ago
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