Question

Coasting due west on your bicycle at 8.4 m/s, you encounter a sandy patch of road 7.2 m across. When you leave the sandy patch, your speed has been reduced to 6.4 m/s. What is the bicycles acceleration in the sandy patch? assume that the acceleration is constant and that the direction of travel is the positive direction.

Answer 1

Answer:

-2.1 m/s²

Explanation:

Given:

v₀ = 8.4 m/s

v = 6.4 m/s

Δx = 7.2 m

Find: a

v² = v₀² + 2aΔx

(6.4 m/s)² = (8.4 m/s²) + 2a (7.2 m)

a = -2.1 m/s²