Coasting due west on your bicycle at 8.4 m/s, you encounter a sandy patch of road 7.2 m across. When you leave the sandy patch,
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Answer:
a. E = -13.8 kN/C
b. E = +8.51 kN/C
Explanation:
We will apply Gauss' Law to the regions where the electric field is asked.
Gauss' Law states that if you draw an imaginary surface enclosing a charge distribution, then the electric field through the imaginary surface is equal to the total charge enclosed by this surface divided by electric permittivity.
a. For this case, we will draw the imaginary surface between the inner and outer shell of the sphere. The total charge enclosed by this surface will be equal to the sum of the charge Q at the center and charge of the shell within the volume from R1 and r.
Here, r = 0.5(R1+R2) = 12 cm.
b. For this case, we will draw the imaginary surface on the outside of the shell.
The total charge enclosed by this surface will be equal to the sum of the charge at the center and the total charge of the shell.
Answer:
-3 m/s²
Explanation:
average acceleration formula: (final velocity - initial velocity) ÷ time
FV: 18 m/s
IV: 30 m/s
T: 4 s
that is equal to -3
hopefully this is correct :)