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andrew-mc [135]
3 years ago
13

A ball is tossed vertically upward. When it reaches its highest point (before falling back downward) Group of answer choices the

velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward. the velocity is zero, the acceleration is zero, and the force of gravity acting on the ball is zero. the velocity is zero, the acceleration is zero, and the force of gravity acting on the ball is directed downward. the velocity and acceleration reverse direction, but the force of gravity on the ball remains downward. the velocity, acceleration, and the force of gravity on the ball all reverse direction.
Physics
1 answer:
nignag [31]3 years ago
7 0

Answer:

the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward

Explanation:

Is this exercise in kinematics

          v = v₀ - g t

where g is the acceleration of the ball, which is created by the attraction of the ball to the Earth.

At the highest point

velocity must be zero.

The acceleration depends on the Earth therefore it is constant at this point and with a downward direction.

The force of the earth on the ball is towards the center of the Earth, that is, down

all other alternatives are wrong

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A 1-kg rock is suspended by a massless string from one end of a
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The weight of measuring stick is 9.8 N

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F_{r} d - F_{s}d = 0

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6 0
3 years ago
When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo
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Answer:

46.4 s

Explanation:

5 minutes = 60 * 5 = 300 seconds

Let g = 9.8 m/s2. And \theta be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim .  Both of their motions are subjected to parallel component of the gravitational acceleration gsin\theta

Rob equation of motion can be modeled as s = a_Rt_R^2/2 = a300^2/2 = 45000a[/tex]

Jim equation of motion is s = a_Jt_J^2/2 = (3a/4)t_J^2/2 = 3at_J^2/8

As both of them cover the same distance

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t_J = \sqrt{120000} = 346.4 s

So Jim should start 346.4 – 300 = 46.4 seconds earlier than Rob in other to reach the end at the same time

7 0
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