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4 years ago

Who is Tim peak where did he come from

1 answer:

8 0

I believe you mean Tim Peake ? .Major Timothy Nigel "Tim" Peake CMG is a British Army Air Corps officer, European Space Agency astronaut and International Space Station crew member.

Born: April 7, 1972 (age 44), Chichester, United Kingdom

Space missions: Expedition 46, Expedition 47, Soyuz TMA-19M

Nationality: British

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An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force

sweet-ann [11.9K]

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = $10ms^{-2}$ , F = ma = 15*10 = 150N

2) m = 3kg, v = $4ms^{-1}$ , r = 4m, F = $\frac{mv^{2} }{r}$

$\frac{3*4^{2} }{4}$ = 12N

3) a = $10ms^{-2}$ , r = 10m, v=?

F = $\frac{mv^{2} }{r}$ and F = ma

equating the two equations and cancelling a, we have:

$\frac{v^{2} }{r}$ = a

making v the subject of formula, we have:

v = $\sqrt{ar}$

= $\sqrt{100}$

= 10 $ms^{-1}$

4) r = 10m, v = $5ms^{-1}$ , a = ?

F = $\frac{mv^{2} }{r}$

F = ma

equating the above equations and making a subject of formula, we get:

a = $\frac{v^{2} }{r}$

a = 25/10 = 2.5 $ms^{-2}$

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is tripled

F = $(3v)^{2}$

F = 9 $v^{2}$

We can see that the force will be 9X greater than it was.

9) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is doubled

F = $(2v)^{2}$

F = 4 $v^{2}$

We can see that the force will be 4X greater than it was.

10) F = $\frac{mv^{2} }{r}$

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

7 0

3 years ago

A three-way 120 V lamp bulb that contains two filaments is rated for 100-200-300 W. One filament burns out. Afterward, the bulb

ololo11 [35]

Answer:

The larger resistance value is 144 ohms and the smaller resistance value is 48 ohms.

Explanation:

Given that Resistance, R, is inversely proportional to Power, the largest value of power will yield the smallest value of resistance and vice versa.

The largest value of resistance will be:

P = V²/R

R = V²/P

R = 120²/100

R = 144 ohms

The smallest value of resistance will be:

R = 120²/300

R = 48 ohms

8 0

4 years ago

A 20 kg girl runs up the staircase to a floor 4 m higher in 5 seconds. Whats her power output?

Zina [86]

Answer:

Explanation:

P = mgh/t = 20(9.8)(4) / 5 = 156.8 W(atts)

6 0

2 years ago

Waves from a radio station have a wavelength of 369 m. They travel by two paths to a home receiver 20.0 km from the transmitter.

Olenka [21]

Answer:

92.25m

Explanation:

In order to solve the exercise, it is necessary to apply the concept of construtive interference due to a path difference.

The formula is given by,

$\delta = (m+\frac{1}{2})\frac{\lambda}{n}$

where,

n is the index of refraction of the medium in which the wave is traveling

$\lambda =$ wavelenght

$\delta =$ is the path difference

m = integer (0,1,2,3...)

Since in this case we are dealing with an atmospheric environment, where air is predominant, we approximate n to 1.

And since we need the reflected wave,

$\delta = 2x$

Where x is the distance in one direction without return.

The distance must correspond to the minimum therefore m = 0, so

$\delta = (m+\frac{1}{2})\frac{\lambda}{n}$

$\delta = ({0+\frac{1}{2})\frac{369}{1}$

$\delta = 184.5m$

Then the minimum distance is:

$x= \frac{delta}{2}$

$x = \frac{184.6}{2}$

$x = 92.25m$

Therefore the minimum distance from the mountain to the receiver that produces destructive interference at the receiver is 92.25m

5 0

3 years ago

An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How

Alborosie

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

$g=24 m/s^2$

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

$s=0+\frac{1}{2}(24)(1)^2=12 m$

6 0

4 years ago