Answer:
v = 3.04 m/s
Explanation:
given,
mass of the block, M = 6.6 Kg
horizontal force, F = 12.2 N
distance, L = 2.5 m
initial speed = 0 m/s
speed of the block,v = ?
we now
Work done is equal to change in Kinetic energy.
Work done = Force x displacement
W = Δ K E
Δ K E = Force x displacement
3.3 v² = 30.5
v² = 9.242
v = 3.04 m/s
speed of the block is equal to 3.04 m/s
The two subatomic particles that contribute to the net charge of an ion are electrons and protons.
<h3>What is an atom?</h3>
Atom is the smallest possible amount of matter which still retains its identity as a chemical element, now known to consist of a nucleus surrounded by electrons.
The atom is made up of three components called subatomic particles as follows;
The proton is the positively charged subatomic particle forming part of the nucleus of an atomwhile the electron is the subatomic particle having a negative charge and orbiting the nucleus.
This suggests that the two subatomic particles that contribute to the net charge of an ion are electrons and protons. That is;
Net charge = protons - electrons
Learn more about subatomic particles at:brainly.com/question/13303285
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We have here what is known as parallel combination of resistors.
Using the relation:
And then we can turn take the inverse to get the effective resistance.
Where r is the magnitude of the resistance offered by each resistor.
In this case we have,
(every term has an mho in the end)
To ger effective resistance take the inverse:
we get,
The potential difference is of 9V.
So the current flowing using ohm's law,
V = IR
will be, 0.0139 Amperes.
It is difficult for astronomers to find object like planets and asteroids because it takes a lot of time to verify the objects locations and what surrounds a certain object in order to prove and be precise of its location
"Frequency decreases" is the one way among the following choices given in the question that <span>frequency change as wavelength increases. The correct option among all the options that are given in the question is the second option. I hope that this is the answer that has actually come to your desired help.</span>
