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3 years ago

8. At what position does the mass have the greatest acceleration?

Physics

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

Option (e)

Explanation:

If a mass attached to a spring is stretched and released, it follows a simple harmonic motion.

In simple harmonic motion, velocity of the mass will be maximum, kinetic energy is maximum and acceleration is 0 at equilibrium position (at 0 position).

At position +A, mass will have the minimum kinetic energy, zero velocity and maximum acceleration.

Therefore, Option (e) will be the answer.

You might be interested in

A copper wire is stretched so that its length increases and its diameter decreases. what is the result?

Dovator [93]

The result is although the wire's resistivity doesn't change, its resistance does.

Considering the formula for a material's resistance:

R=pL/A

R is directly proportional to L and inversely proportional to A, as can be seen. Be aware that "rho" is a material-specific and intensive attribute (meaning this value will not change if the material is only physically altered). Remember that A = This implies that the relationship between R and the square of r is inverse. When the wire is stretched, the impacts on length are less noticeable than the effects on r. Therefore the wire's resistance increases, but its resistivity stays the same.

Learn more about resistance here:

brainly.com/question/20708652

#SPJ4

3 0

2 years ago

When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s . By how much has thermal energy increased duri

Advocard [28]

Complete question:

A fireman of mass 80 kg slides down a pole. When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s. By how much has thermal energy increased during his slide?

Answer:

The thermal energy increased by 3,099.2 J

Explanation:

Given;

mass of the fireman, m = 80 kg

initial position of the fireman, hi = 4.2 m

final speed, v = 2.2 m/s

The change in the thermal energy is calculated as;

ΔE + (K.Ef - K.Ei) + (Uf - Ui) = 0

where;

ΔE is the change in the thermal energy

K.Ef is the final kinetic energy

K.Ei is the initial kinetic energy

Uf is the final potential energy

Ui is the initial potential energy

$\Delta E_{th} + (\frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2) + (mgh_f - mgh_i)=0\\\\initial \ velocity, \ v_i = 0\\final \ height , \ h_f = o\\\\\Delta E_{th} + (\frac{1}{2} mv_f^2) + ( - mgh_i)=0\\\\\Delta E_{th} + \frac{1}{2} mv_f^2 - mgh_i = 0\\\\\Delta E_{th} =mgh_i - \frac{1}{2} mv_f^2\\\\\Delta E_{th} = 80 \times 9.8 \times 4.2 \ \ - \ \ \frac{1}{2} \times 80 \times (2.2)^2 \\\\\Delta E_{th} = 3292.8 \ J \ - \ 193.6 \ J\\\\\Delta E_{th} = 3,099.2 \ J$

3 0

3 years ago

A 1000kg roller coaster begins at 10m tall hill with initial velocity of 6m/s and travels down until a second hill. 1700J is tra

nadezda [96]

Answer:

The maximum height could be 10.6 meters.

Explanation:

For this kind of exercise, we use the general principle for conservation of mechanical energy (E) that states:

$E_1+W_f=E_2$ (1)

That means the mechanical energy an object has on a point 2 should be equal to the mechanical energy on a point 1 plus the energy transformed into heat due friction denoted as Wf (It is negative because is lost). In our case point 1 is the point where the roller coaster begins and point 2 is at the second hill. Tola mechanical energy is the sum of potential gravitational energy and kinetic energy, so (1) is :

$K_{1}+U_{1}+W_{f}=K_{2}+U_{2}$

with K the kinetic energy and U the potential energy, remember potential energy is mgh and kinetic energy is $\frac{mv^2}{2}$ with m the mass, v the velocity and h the height, then:

$\frac{mv_1^2}{2}+mgh_1+W_{f}=\frac{mv_2^2}{2}+mgh_2$

Solving for h_2:

$h_2=\frac{\frac{mv_1^2}{2}+mgh_1+W_{f}-\frac{mv_2^2}{2}}{mg}=\frac{\frac{(1000)(6)^2}{2}+(1000)(9.8)(10)-1700-\frac{(1000)(4.6)^2}{2}}{(1000)(9.81)}$

$h_2=10.6 m$

4 0

3 years ago

How does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at

Maru [420]

Well you of course have different kinetic energies with the two speeds.
Kinetic energy = (1/2)*mass*velocity^2
The vehicle's mass is the same in both cases, so we can ignore that as well as 1/2 since it's a constant.
So we have (30)^2 vs (60^2)
which is 900 vs 3600
So having 60 mph compared to 30 mph is 4 times the kinetic energy.

5 0

3 years ago

I CANT COUNT FOR MY LIFE

timurjin [86]

Answer:

Lol it was the last one

Explanation

something

6 0

3 years ago

Read 2 more answers